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notsponge [240]
3 years ago
11

4 (x+5)=3 (x-2)-2 (x+2)

Mathematics
2 answers:
Vesna [10]3 years ago
7 0
4x+20=3x-6-2x-4
4x+20=x-10
4x-x=-10-20
3x=-30
X=-10
Brrunno [24]3 years ago
6 0
4x+5=3x-6-2x-4
4x+5=x-10
4x+15=x
3x+15=0
3x=-15
x=-5
I think that's right
Happy Holidays
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What is the equation of the line that passes through the points (-1, 7) and (2, 10) in Standard Form?
Usimov [2.4K]

bearing in mind that standard form for a linear equation means

• all coefficients must be integers, no fractions

• only the constant on the right-hand-side

• all variables on the left-hand-side, sorted

• "x" must not have a negative coefficient

\bf (\stackrel{x_1}{-1}~,~\stackrel{y_1}{7})\qquad (\stackrel{x_2}{2}~,~\stackrel{y_2}{10}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{10-7}{2-(-1)}\implies \cfrac{3}{2+1}\implies \cfrac{3}{3}\implies 1

\bf \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-7=1[x-(-1)]\implies y-7=x+1 \\\\\\ y=x+8\implies \boxed{-x+y=8}\implies \stackrel{\textit{standard form}}{x-y=-8}

just to point something out, is none of the options, however -x + y = 8, is one, though improper.

3 0
3 years ago
Find the 15th term of the arithmetic sequence whose common difference is d=9 and whose first term is a, = 2.
Alenkinab [10]
Nose rkrbtje de donde salió la luz de
6 0
3 years ago
Will rate you brainliest
GREYUIT [131]

Answer:

\frac{11x}{3y}

Step-by-step explanation:

\frac{7x}{3y} + \frac{12x}{9y}

Make both a single fraction by adding together.

\frac{3(7x) + 1(12x)}{9y}

\frac{21x + 12x}{9y}

\frac{33x}{9y}

Simplify

\frac{3(11)x}{3(3y)}

\frac{11x}{3y}

5 0
3 years ago
I need help with this!
7nadin3 [17]

Answers:

  1. False
  2. True
  3. True
  4. False
  5. True
  6. False

===============================================

Explanations:

  1. If we can write a number as a ratio (or fraction) of two whole numbers, then that number is considered rational. The denominator can never be 0. In the case of 6/4, this is a rational number. Therefore, the statement "6/4 is irrational" is false.
  2. This is a true statement. We cannot write sqrt(2) as a fraction of two integers. The proof of this is fairly lengthy, but one way is to use a proof by contradiction to show that sqrt(2) = a/b is impossible. Since we cannot make sqrt(2) into a ratio of two integers, we consider it irrational.
  3. This is a true statement. Any terminating decimal is always rational. In this case, 1.3 = 13/10.
  4. This is false. Any repeating decimal can be converted to a fraction through a bit of work. It turns out that 17.979797... = 1780/99 which makes the value to be rational.
  5. Any integer is rational. We can write the integer over 1. So something like -16 is the same as -16/1, showing how it is rational. So that's why this statement is true.
  6. This statement is false because we found true statements earlier.

4 0
3 years ago
HI umm CAN YOU PLEASE ANSWER ASAP!!!!
Marianna [84]

Answer:

2

Step-by-step explanation:

-6 divided by a positive number would make it a positive number welcome

8 0
3 years ago
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