All categories

3 years ago

Show your work, 10-5x =20

2 answers:

5 0

The best part of this problem is that it has one unknown variable in the form of "x" and a single equation. So getting to the desired solution becomes very easy.
The equation given in the question is
10 - 5x = 20
- 5x = 20 - 10
- 5x = 10
- x = 10/5
- x = 2
Multiplying both sides with -1 we get
x = -2
So the value of x is -2. I hope the procedure is clear enough for you to understand.

Ilia_Sergeevich [38]3 years ago

3 0

10-5x=20
-10 -10
-5x=10
-5 =-5
x=-2

You might be interested in

15+(12+8a) simplify and justify each step

ki77a [65]

1. distribute a 1 to the 12 and 8a
2. you'll get 15+ 12 +8a
3. add the like terms(15 and 12)
4. your final answer will be 27+8a

5 0

3 years ago

Read 2 more answers

A bag of pecans costs $3.84. If

Stels [109]

Answer:

10.4 cents

Step-by-step explanation:

40 pecans/$3.84 gives you pecans per dollar

6 0

3 years ago

I don't know how to do this

Gre4nikov [31]

Answer:

x = -11/5 and y = 24/5

Step-by-step explanation:

Use elimination.

First, we need to multiply so that at least one variable can cancel out.

We can multiply the top equation by 2.

So we get

4x + 6y = 20

Then, we can use elimination.

The x's cancel out.

So we get 5y = 24

Or y = 24/5

Then, we can plug in this y value back into the first equation to find x.

2x + 3(24/5) = 10

2x + 72/5 = 50/5

2x = -22/5

x = -11/5

So x = -11/5 and y = 24/5

5 0

2 years ago

I have been gone for a long time TIME TO ANSWER STUP!D QUESTION!!!!!!!!!(JK)e Points Free

bezimeni [28]

Answer:

Thanks kind stranger! :)

Step-by-step explanation:

3 0

2 years ago

The vertices of a triangle ABC are A(7, 5), B(4, 2), and C(9, 2). What is measure of angle ABC? 30° 45° 56.31° 78.69°

GenaCL600 [577]

The measure of angle ABC is 45°

Explanation

Vertices of the triangle are: A(7, 5), B(4, 2), and C(9, 2)

According to the diagram below....

Length of the side BC (a) $=\sqrt{(4-9)^2+(2-2)^2}= \sqrt{25}= 5$

Length of the side AC (b) $= \sqrt{(7-9)^2 +(5-2)^2}= \sqrt{4+9}=\sqrt{13}$

Length of the side AB (c) $= \sqrt{(7-4)^2 +(5-2)^2} =\sqrt{9+9}=\sqrt{18}$

We need to find ∠ABC or ∠B . So using Cosine rule, we will get...

$cosB= \frac{a^2+c^2-b^2}{2ac} \\ \\ cos B= \frac{(5)^2+(\sqrt{18})^2-(\sqrt{13})^2}{2*5*\sqrt{18} }\\ \\ cosB= \frac{25+18-13}{10\sqrt{18}} =\frac{30}{10\sqrt{18}}=\frac{3}{\sqrt{18}}\\ \\ cosB=\frac{3}{3\sqrt{2}} =\frac{1}{\sqrt{2}}\\ \\ B= cos^-^1(\frac{1}{\sqrt{2}})= 45 degree$

So, the measure of angle ABC is 45°

7 0

3 years ago

Read 2 more answers