Answer:
1 cm^2 = 100 mm^2
9 cm^2 = 900 mm^2
5.2 cm^2 = 520 mm^2
1 dm^2 = 100 cm^2
17 dm^2 = 1700 cm^2
4.3 dm^2 = 430 cm^2
1 m^2 = 10000 cm^2
7 m^2 = 70000 cm^2
2.5 m^2 = 25000 cm^2
1 km^2 = 1000000 m^2
50 km^2 = 50000000 m^2
8.5 km^2 = 8500000 m^2
Step-by-step explanation:
1 cm = 10 mm
1
= 10×10
= 100
9
= 9×100
= 900 
5.2
= 5.20×100
= 520 
1 dm = 10 cm
1
= 10×10
= 100 
17
= 17× 100
= 1700 
4.3
= 4.3 × 100
= 430 
1 m = 100 cm
1
= 100×100
= 10000 
7
= 7×10000
= 70000 
2.5
= 2.5×10000
= 25000 
1 km = 1000 m
1
= 1000×1000
= 1000000 
50
= 50×1000000
= 50000000 
8.5
= 8.5×1000000
= 8500000 
The question is asking to calculate the average speed of the mail truck if it travels 82 miles in just 412 hours, base on that, the possible answer would be that the average speed of the truck is 0.2 miles per hour. I hope you are satisfied with my answer and feel free to ask for more
We know that
The Standard Form of a Quadratic Equation<span> looks like this
</span> ax²<span> + bx + c = 0
</span>
we have
<span>x -1 0 1 2 3
y -20 -6 2 4 0
for x=0 y=-6
then
</span> y=ax² + bx + c --------> -6=a*0² + b*0 + c ---------> c=-6
for y=0 x=3
then
y=ax² + bx + c-------> 0=a*3² + b*3 -6---------> 9a+3b=6----> equation 1
for x=2 y=4
then
y=ax² + bx +
c-----> 4=a*2² + b*2 -6-----> 4=4a+2b-6-----> 4a+2b=10---->
a=2.5-0.5b----> equation 2
I substitute 2 in 1
9*[2.5-0.5b]+3b=6------>
22.5-4.5b+3b=6------> 1.5b=16.5------> b=11
a=2.5-0.5*11------>
a=2.5-5.5------> a=-3
The Standard
Form of a Quadratic Equation is
ax² + bx + c
= 0--------> -3x²+11x-6=0
the answer is
-3x²+11x-6=0
See the attached figure
Answer:
a=1, b=1
Step-by-step explanation:
Given the equation: 
If the solution of the equation 
Then to find the values of a and b, we substitute
into the equation.
