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3 years ago

What is the first step to simplify the expression 64^42-[2(4-6)2]?

Mathematics

1 answer:

Marat540 [252]3 years ago

3 0

Simplify what's in brackets first, then move to what's in the parenthesis

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A new crew of painters can paint a small apartment in 12 hours. an experienced crew can paint the small apartment in 6 hours. ho

Yakvenalex [24]

This is the concept of proportionality, we are required to calculate for the number of hours two crews can use to paint the house altogether.
Here proceed as follows;
number of hours new crew can paint=12 hrs
portion of work painted by new crew in 1 hour= 1/12

number of hours experienced crew can paint=6 hours
Portion of work painted by experienced crew in 1 hour=1/6

Portion of work painted by the two crews altogether in 1 hour will be:
1/6+1/12=1/4

thus the total amount of hours that the two painters will take to paint will be:
4 hours

6 0

4 years ago

Convert the decimal below into a rational number.

LekaFEV [45]

The answer is D.1/10

3 0

3 years ago

Solve using Fourier series.

Olin [163]

With $2L=\pi$ , the Fourier series expansion of $f(x)$ is

$\displaystyle f(x)\sim\frac{a_0}2+\sum_{n\ge1}a_n\cos\dfrac{n\pi x}L+\sum_{n\ge1}b_n\sin\dfrac{n\pi x}L$
$\displaystyle f(x)\sim\frac{a_0}2+\sum_{n\ge1}a_n\cos2nx+\sum_{n\ge1}b_n\sin2nx$

where the coefficients are obtained by computing

$\displaystyle a_0=\frac1L\int_0^{2L}f(x)\,\mathrm dx$
$\displaystyle a_0=\frac2\pi\int_0^\pi f(x)\,\mathrm dx$

$\displaystyle a_n=\frac1L\int_0^{2L}f(x)\cos\dfrac{n\pi x}L\,\mathrm dx$
$\displaystyle a_n=\frac2\pi\int_0^\pi f(x)\cos2nx\,\mathrm dx$

$\displaystyle b_n=\frac1L\int_0^{2L}f(x)\sin\dfrac{n\pi x}L\,\mathrm dx$
$\displaystyle b_n=\frac2\pi\int_0^\pi f(x)\sin2nx\,\mathrm dx$

You should end up with

$a_0=0$
$a_n=0$
(both due to the fact that $f(x)$ is odd)
$b_n=\dfrac1{3n}\left(2-\cos\dfrac{2n\pi}3-\cos\dfrac{4n\pi}3\right)$

Now the problem is that this expansion does not match the given one. As a matter of fact, since $f(x)$ is odd, there is no cosine series. So I'm starting to think this question is missing some initial details.

One possibility is that you're actually supposed to use the even extension of $f(x)$ , which is to say we're actually considering the function

$\varphi(x)=\begin{cases}\frac\pi3&\text{for }|x|\le\frac\pi3\\0&\text{for }\frac\pi3$

and enforcing a period of $2L=2\pi$ . Now, you should find that

$\varphi(x)\sim\dfrac2{\sqrt3}\left(\cos x-\dfrac{\cos5x}5+\dfrac{\cos7x}7-\dfrac{\cos11x}{11}+\cdots\right)$

The value of the sum can then be verified by choosing $x=0$ , which gives

$\varphi(0)=\dfrac\pi3=\dfrac2{\sqrt3}\left(1-\dfrac15+\dfrac17-\dfrac1{11}+\cdots\right)$
$\implies\dfrac\pi{2\sqrt3}=1-\dfrac15+\dfrac17-\dfrac1{11}+\cdots$

as required.

5 0

3 years ago

Find the x and y intercept and the slope of the graph of 8x-6y=24

andreev551 [17]

Answer:

the x intersept is 3 the y intercept is 4

Step-by-step explanation:

x intersept : 24/8 = 3

y intersept : 24/6 =4

4 0

3 years ago

Point G is between F and H on line FH. Use the given information solve for x and then find FG AND GH.

Viktor [21]

Answer:

X=6

FG=31

GH=22

Step-by-step explanation:

Equation: FG+GH=FH

rewrite with values

4x+7 + 5x-8 = 53

combine like terms

9x-1 = 53

add 1 to both sides

9x = 54

divide by 9

x = 6

use 6 end solve for FG and GH

FG = 4(6) + 7 = 31

GH = 5(6) - 8 = 22

Check your answers.. Do FG and GH add up to equal FH (53)?

31 + 22 = 53

I hope this made sense.

7 0

3 years ago