Solution:
<u>Note that:</u>
- Speed = Distance/Time
- Vaimiti speed = 1.1 m/s
- Jabril speed = 1.3 m/s
<u>Converting the time (minutes to seconds) for Vaimiti to reach school:</u>
- Vaimiti's time to reach school: 25 minutes = 25 x 60 seconds
- => Vaimiti's time to reach school: 1500 seconds
<u>Converting the time (minutes to seconds) for Jabril to reach school:</u>
- Jabril's time to reach school: 30 minutes = 30 x 60 seconds
- => Jabril's time to reach school: 1800 seconds
<u>Finding the distance of Vaimiti:</u>
Important: <em>The distance will be in meters since the speed units is </em><u><em>meters</em></u><em>/seconds.</em>
- => 1.1 meters/second = Distance/1500
- => 1.1 x 1500 = Distance
- => 1650 meters = Distance (In meters)
<u>Finding the distance of Jabril:</u>
Important: <em>The distance will be in meters since the speed units is </em><u><em>meters</em></u><em>/seconds.</em>
- 1.3 meters/second = Distance (In meters)/1800 seconds
- => 1.3 x 1800 = Distance (In meters)
- => 2340 meters = Distance (In meters)
This can lead to two possible solutions:
Possible solution #1:
<u>Finding the difference between the two distances:</u>
- 2340 meters - 1650 meters = Difference (In meters)
- => 690 meters
Possible solution #2:
The difference between the <u>distances they walked</u> is that Jabril walked <u>faster</u> than Vaimiti, but Vaimiti reached <u>school</u> earlier than Jabril because the <u>walking distance</u> for Vaimiti is less than the <u>walking</u> <u>distance</u> for Jabril.
Hoped this helped!
Answer:
$51.70
Step-by-step explanation:
I don't know how to explain it actually so I am just going to do this...
y= 0.1(x + 20) +7
y=0.1x + 2 + 7
y=0.1x +9
y=0.1(427)+9
y=42.7+9
y=51.7
So, maybe the answer is $51.70.
- I’m assuming the expression implies the following:
(1-n)/(n^2 - 1)
The steps goes as follows:
= -(n-1)/(n^2-1) (factored a negative out)
= -(n-1)/[(n+1)(n-1)] (Factored denominator into a difference of squares, but don’t just blindly accept the fact, expand it and you should get the original denominator)
At this point, the (n-1) terms cancel, as you should know: a real number, besides 0, over itself is 1.
= -1/(n+1) , which is the answer
Note: You could also see it as 1/-(n+1) or 1/(-n-1)
Answer:
3•10^3 is 3,000, so the answer is 9,000
Answer:
It's going to be B and E because it's in the hundreds place not in the tens or whole
