Http://mathsfirst.massey.ac.nz/Algebra/SystemsofLinEq/EMeth.htm this website explains it well
Answer:
Sum = 15 8/15, Difference = 1 2/15
Step-by-step explanation:
8⅓, 71/5
A. Sum
8⅓ + 7 1/5
Convert to improper fraction
25/3 + 36/5
Find the LCM of 3 and 5. The result is 15. Divide 15 by the denominator of each fraction and multiply the result obtained with the numerator. The result is shown below:
[(25×5) + (36×3)] / 15
[125 + 108] / 15
233 / 15
Convert to mixed fraction
15 8/15
B. Difference
8⅓ – 7 1/5
Convert to improper fraction
25/3 – 36/5
Find the LCM of 3 and 5. The result is 15. Divide 15 by the denominator of each fraction and multiply the result obtained with the numerator. The result is shown below:
[(25×5) – (36×3)] / 15
[125 – 108] / 15
17 / 15
Convert to mixed fraction
1 2/15
SUMMARY:
Sum = 15 8/15, Difference = 1 2/15
Answer:
Step-by-step explanation:
As an example, iodine-131 is a radioisotope with a half-life of 8 days. It decays by beta particle emission into xenon-131. After eight days have passed, half of the atoms of any sample of iodine-131 will have decayed, and the sample will now be 50% iodine-131 and 50% xenon-131.
50 grams to 25 grams is one half-life. 25 grams to 12.5 grams is another half-life. So, for 50 grams to decay to 12.5 grams, two half-lives, which would take 36 days total, would need to pass. This means each half-life for element X is 18 days.
Answer:
They delete it use quizlet
Step-by-step explanation:
QUIZLET
Should be a scale factor of y= 1/9
