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nikdorinn [45]
3 years ago
6

True or false? Help will make brainliest !​

Mathematics
2 answers:
satela [25.4K]3 years ago
6 0

True is the correct answer.

AlexFokin [52]3 years ago
3 0

Answer: true

Step-by-step explanation:

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Step-by-step explanation:

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A rectangle has the following vertices. Find the area of the rectangle. (9, −1), (−1, 7), (−5, 2), (5, −6)
stiks02 [169]

Answer:  82 sq. units .

Step-by-step explanation:

Let A (9, −1), B (−1, 7), C(−5, 2), D(5, −6) are the vertices of rectangle.

Then we plot them on graph ( as provided in attachment)

Length = AB =\sqrt{(9+1)^2+(-1-7)^2} units  [By distance formula : \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}]

=\sqrt{(10)^2+(-8)^2}=\sqrt{100+64}=\sqrt{164}=2\sqrt{41} units

Width = BC = \sqrt{(-1+5)^2+(7-2)^2} units

=\sqrt{4^2+5^2}\\\\=\sqrt{16+25}\\\\=\sqrt{41}

Area = length x width

= 2\sqrt{41}\times\sqrt{41}=2\times41= 82\text{ sq. units}

Hence, the  area of the rectangle is 82 sq. units .

7 0
3 years ago
The endpoints of a regular pentagon are (-1,4) and (2,3). What is the perimeter of the Pentagon?
ryzh [129]

the assumption being that the endpoints are two continuous points in the pentagon, Check picture below.

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-1}~,~\stackrel{y_1}{4})\qquad (\stackrel{x_2}{2}~,~\stackrel{y_2}{3})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ d=\sqrt{[2-(-1)]^2+[3-4]^2}\implies d=\sqrt{(2+1)^2+(3-4)^2} \\\\\\ d=\sqrt{9+1}\implies d=\sqrt{10}~\hfill \stackrel{\stackrel{~\hfill \stackrel{\textit{5 sides}}{}}{\textit{perimeter of the pentagon}}}{5\sqrt{10}}

4 0
2 years ago
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