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3 years ago

Why is it important for scientists to review and repeat the work of other scientists?

Chemistry

2 answers:

barxatty [35]3 years ago

4 0

Select one:

a. ensure the results are in agreement with accepted scientific beliefs

b. guarantee federal funding by supporting each other's work

c. keep the science community better informed

d. validate the results and check the evidence's reliability

ANSWER IS D

Andrej [43]3 years ago

3 0

To confirm the results of the same experiment to see if they are similar

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If a combination reaction takes place between potassium and chlorine what is the product

zepelin [54]

It would be potassium chloride or kcl

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3 years ago

If the natural abundance of Ag-107 is 51.84% what is the abundance of Ag-109?

ASHA 777 [7]

Answer:

Explanation:

48.16%

Well, both abundances have to total 100% so is Ag-107 is 51.84%, then Ag-109 must be 100 – 51.84 = 48.16%.

Hope This Helps :)

4 0

2 years ago

Bromination occurs on alkene functional groups, but NOT on alkenes found within aromatic functional group, such as the phenyl ri

liq [111]

Answer:

When cinnamic acid react with bromine ,addition reaction rapidly occur on alkene functional group to form dibromo product

Explanation:

Phenyl ring is an aromatic hydrocarbon ,when aromatic hydrocarbons react with Cl2,Br2 or KMnO4 no reaction occur ,where as unsaturated hydrocarbon like alkene react .Aromatic hydrocarbon with these reagents undenr different conditions undergoes subtituition reaction.They react with bromine in presence of lewis acid catalyst ferric bromide.

8 0

3 years ago

This decomposition is first order with respect to phosphine, and has a half‑life of 35.0 s at 953 K. Calculate the partial press

Solnce55 [7]

Answer:

0.57 atm

Explanation:

When a a reaction is first order, we have from calculus the following relation:

ln[A]t/[A]₀ = - kt

where [A]t is the concentration of A ( phosphine in this case ) after a time, t

[A]₀ is the initial concentration of A

k is the rate constant, and

t is the time

We also know that for a first order reaction

k = 0.693/ t 1/2

wnere t 1/2 is the half-life.

This equation is derived for the case when A]t/= 1/2 x [A]₀ which occurs at the half-life.

Thus, lets first find k from the half life time, and then solve for t = 70.5 s

k = 0.693 / 35.0 s = 0.0198 s⁻¹

ln [ PH₃ ]t / [ PH₃]₀ = - kt

from the ideal gas law we know pV = nRT, so the volumes cancel:

ln (pPH₃ )t / p(PH₃)₀ = - kt

taking inverse log to both sides of the equation:

(pPH₃ )t / p(PH₃)₀ = - kt

thus:

(pPH₃ )t = 2.29 atm x e^(- 0.0198 s⁻¹ x 70.5 s ) = 0.57 atm

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3 years ago

HELPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP

Trava [24]

Answer:

b..................

4 0

2 years ago

Read 2 more answers