The grams that would be produced  from 7.70 g of butanoic acid and excess ethanol is  7.923grams
calculation
Step 1: write the chemical equation for the reaction
CH3CH2CH2COOH + CH3CH2OH →  CH3CH2CH2COOCH2CH3  +H2O
step 2: find the moles of butanoic acid
moles= mass/ molar mass
=  7.70 g/ 88 g/mol=0.0875 moles
Step 3:  use the mole ratio to determine the moles of ethyl butyrate
moles ratio of CH3CH2CH2COOH :CH3CH2CH2COOCH2CH3  is 1:1 therefore the moles of CH3CH2CH2COOCH2CH3 = 0.0875  x78/100=0.0683moles
step 4: find mass = moles x molar mass
  =  0.0683 moles  x116 g/mol=7.923grams
 
        
                    
             
        
        
        
Answer:
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Explanation:
 
        
             
        
        
        
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Explanation:
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Answer:
The concentration of chloride ion is 
Explanation:
We know that 1 ppm is equal to 1 mg/L.
So, the  content 100 ppm suggests the presence of 100 mg of
 content 100 ppm suggests the presence of 100 mg of  in 1 L of solution.
 in 1 L of solution.
The molar mass of  is equal to the molar mass of Cl atom as the mass of the excess electron in
 is equal to the molar mass of Cl atom as the mass of the excess electron in  is negligible as compared to the mass of Cl atom.
 is negligible as compared to the mass of Cl atom.
So, the molar mass of  is 35.453 g/mol.
 is 35.453 g/mol.
Number of moles = (Mass)/(Molar mass)
Hence, the number of moles (N) of  present in 100 mg (0.100 g) of
 present in 100 mg (0.100 g) of  is calculated as shown below:
 is calculated as shown below:

So, there is  of
 of  present in 1 L of solution.
 present in 1 L of solution.