Answer:
28.6 mL
Explanation:
Step 1: Write the balanced neutralization reaction between acetic acid and sodium hydroxide
CH₃COOH(aq) + NaOH(aq) = CH₃COONa(aq) + H₂O(l)
Step 2: Calculate the moles of acetic acid
The molar mass of acetic acid is 60.05 g/mol. The moles corresponding to 0.120 g are:
Step 3: Calculate the moles of sodium hydroxide
The molar ratio of CH₃COOH to NaOH is 1:1. The reacting moles of NaOH are 2.00 × 10⁻³ mol.
Step 4: Calculate the volume of the 0.0700 M NaOH solution
Based on the enthalpy of the reaction, 41625 kJ of heat is needed to produce 1850 grams of ammonia (NH3).
<h3>What is heat of reaction?</h3>
The heat of reaction or enthalpy change is the heat absorbed or evolved when reactant molecules react to form products.
According the enthalpy value of the reaction, 4 moles of ammonia require 1530 kJ of heat for its formation.
Molar mass of ammonia = 17 g
Mass of 4 moles of ammonia = 4 × 17 = 68 g
1850 g of ammonia will require = 1850 × 1530/68 = 41625 kJ of heat.
Therefore, 41625 kJ of heat is needed to produce 1850 grams of ammonia (NH3).
Learn more about enthalpy at: brainly.com/question/14047927
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Answer:
131.5177 grams
Explanation:
You divide by Avogadro's number to turn it into moles then multiply by molar mass.
Proton mass = 1.672 x 10^-27 kilo. So the approximate mass of a proton would be 1 g or kg.
