I am guessing that your solutions of HCl and of NaOH have approximately the same concentrations. Then the equivalence point will occur at pH 7 near 25 mL NaOH.
The steps are already in the correct order.
1. Record the pH when you have added 0 mL of NaOH to your beaker containing 25 mL of HCl and 25 mL of deionized water.
2. Record the pH of your partially neutralized HCl solution when you have added 5.00 mL of NaOH from the buret.
3. Record the pH of your partially neutralized HCl solution when you have added 10.00 mL, 15.00 mL and 20.00 mL of NaOH.
4. Record the NaOH of your partially neutralized HCl solution when you have added 21.00 mL, 22.00 mL, 23.00 mL and 24.00 mL of NaOH.
5. Add NaOH one drop at a time until you reach a pH of 7.00, then record the volume of NaOH added from the buret ( at about 25 mL).
6. Record the pH of your basic HCl-NaOH solution when you have added 26.00 mL, 27.00 mL, 28.00 mL, 29.00 mL and 30.00 mL of NaOH.
7. Record the pH of your basic HCl-NaOH solution when you have added 35.00 mL, 40.00 mL, 45.00 mL and 50.00 mL of NaOH from your 50mL buret.
Answer:
B. K+cation
Explanation:
Not all that sure but hope it will help.
Answer: Physical change doesn't form a new substance and chemical change does
OK,lisen to me slowly,
all define you.all thing
1.Look at peridoic table which one is solid or others.
For example:hydrogen is air.
And you gonna explain what is hydrogen,
2.After look periodic table you will be able to know every element.
3.Dont forget to check your homework.!!
Answer:
Boron Carbonate; B₂(CO₃)₃
Explanation:
For names, carbonide does not exist; that rules out the first option. Carbide refers to just a carbon atom, not carbon and oxygen as in the polyatomic ion carbonate. That rids us of the third option. We are left with boron carbonate with the formula BCO or boron carbonate with the formula B₂(CO₃)₃.
Recall the carbonate polyatomic ion's formula: CO₃²⁻
Thus BCO cannot be the formula.
Option 4 is your answer, Boron Carbonate; B₂(CO₃)₃.
To further check your answer, observe the oxidation states of boron and the polyatomic ion carbonate. Boron can exist in oxidation states of either 2+ or 3+, and carbonate is only 2-; in this formula, boron will exhibit a 3+ state to balance out with carbonate.
2x3+ = 6+; 3x2- = 6-
6+ + 6- = 0; balanced
