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Alkenes on reacting with ozone results in the formation of ozonide which undergo reductive cleavage in presence of dimethyl sulfide to form carbonyl compounds (aldehyde or ketone). Whereas in presence of hydrogen peroxide it undergoes oxidative cleavage to form carboxylic acids or ketones.
Since, A alkene yields 4-heptanone only on treatment with ozone and DMS thus, it implies that both the chains on the side of the double-bond are similar the product is 4-heptanone that means the double bond is present between the chains at the 4th carbon. Therefore the structure of compound A is 4,5-dipropyloct-4-ene.
The reaction is as shown in the image.
The reaction of A with m-CPBA (meta-perchlorobenzoic acid) followed by aqueous acid
is shown in the image.
m-CPBA (meta-perchlorobenzoic acid) is a peracid and forms epoxides on reacting with alkenes.
Answer:
c) Tìm những chất có hàm lượng đồng bằng nhau trong 4 chất : CuO, Cu2O, CuS, Cu2S.
Explanation:
Explanation:
Na represents the neutral element; Sodium. Because of it's atomic number of 11, It has 11 electrons.
Na+ on the other hand represents a cation. The sodium ion has lost an electron, hence the total number of electrons it has = 10.
The K and L shells each have maximum number of electrons they can accommodate. This is given by the formular; 2n^2
K shell = 2 (1)^2 = 2 electrons
L shell = 2 (2)^2 = 8 electrons
Seeing as Na+ has 10 electrons, It completely filled the K and L shells ( 2 + 8 = 10 )