All categories

2 years ago

Can someone help me in the problem above

Mathematics

1 answer:

MrMuchimi2 years ago

6 0

Answer:

The answer is D

Step-by-step explanation:

When solving you get 23/5 this is 4.6 It says that X must be less than or equal to this

You might be interested in

Three times a number plus 12 minus 5 times the same number is 22. What is the number?

Ilia_Sergeevich [38]

Answer:3

Explanation: 3x5=15+12=27-5=22

5 0

3 years ago

If a^20=(a^n)^m what are the values for m and n

Alinara [238K]

N = 2 and m=10. You multiply them

7 0

2 years ago

Addie bought 9 candy bars and ate 1/2 of them. Frankie bought 6 candy bars and ate 2/3 of them

elena-s [515]

Answer:

addie at 4.5 candie bars and frankie had 4

6 0

2 years ago

The rays OM , ON , and OP in the figure, coincide at time t=0. At the same instant of time OM and OP rotate in the plane about p

Lilit [14]

OM and OP will coincide a second time after 120 seconds. You could visualize it as ray OP moving at 3 degrees/second relative to OM.
Using this visualization, we find that OM makes 30*60*3/360 rotations (minutes * 60 * rotational speed/360 degrees in a rotation), which is 15, and that OP makes 30*60*6/360 or 30 rotations, which is 15 more than OM.

4 0

2 years ago

3^x= 3*2^x solve this equation

kompoz [17]

In the equation

$3^x = 3\cdot 2^x$

divide both sides by $2^x$ to get

$\dfrac{3^x}{2^x} = 3 \cdot \dfrac{2^x}{2^x} \\\\ \implies \left(\dfrac32\right)^x = 3$

Take the base-3/2 logarithm of both sides:

$\log_{3/2}\left(\dfrac32\right)^x = \log_{3/2}(3) \\\\ \implies x \log_{3/2}\left(\dfrac 32\right) = \log_{3/2}(3) \\\\ \implies \boxed{x = \log_{3/2}(3)}$

Alternatively, you can divide both sides by $3^x$ :

$\dfrac{3^x}{3^x} = \dfrac{3\cdot 2^x}{3^x} \\\\ \implies 1 = 3 \cdot\left(\dfrac23\right)^x \\\\ \implies \left(\dfrac23\right)^x = \dfrac13$

Then take the base-2/3 logarith of both sides to get

$\log_{2/3}\left(2/3\right)^x = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x \log_{2/3}\left(\dfrac23\right) = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x = \log_{2/3}\left(3^{-1}\right) \\\\ \implies \boxed{x = -\log_{2/3}(3)}$

(Both answers are equivalent)

8 0

2 years ago