Answer:
x=36
Step-by-step explanation:
So, lets go over what we know:
16 is equal to 4/9ths of x.
As a equation, this looks like:
![16 = \frac{4}{9}x](https://tex.z-dn.net/?f=16%20%3D%20%5Cfrac%7B4%7D%7B9%7Dx)
We can begin to solve for x by multiplying both sides by the denominator, 9, which gets us:
![16*9 = 4x](https://tex.z-dn.net/?f=16%2A9%20%3D%204x)
=
![144 = 4x](https://tex.z-dn.net/?f=144%20%3D%204x)
Then we can divide by the coefficent of x, which is 4, to get our answer:
![\frac{144}{4} = x](https://tex.z-dn.net/?f=%5Cfrac%7B144%7D%7B4%7D%20%3D%20x)
=
![36=x](https://tex.z-dn.net/?f=36%3Dx)
This is our answer! Hope this helps! :3
Answer:
A
Step-by-step explanation:
Tanks are the Backbone of the Military, they are needed to destroy the Axis Powers during WW2, they also used Captured Enemy Tanks for studying and Produce New Tanks to Counter them.
Answer:
155.3 m
Step-by-step explanation:
<u>We have:</u>
θ: is the angle measured from the vertical = 75 °
v = is the speed of the submarine = 10 m/s
t = 1 min
The deep of the front end of the submarine at the end of a 1-minute drive is given by the following ratio:
<u>Where:</u>
d: is the distance traveled by the submarine in 1 minute
x: is the deep to find
The distance, d, is:
Now, the deep is:
![x = cos(75)*600 = 155.3 m](https://tex.z-dn.net/?f=%20x%20%3D%20cos%2875%29%2A600%20%3D%20155.3%20m%20)
Therefore, the deep of the front end of the submarine at the end of a 1-minute drive is 155.3 m.
I hope it helps you!
To answer your question, it is shown in the graph below.
y=-3x-6 is parallel to y=-3x-2
I think the answer would have to be D. $0.90.
59,970-58,800=1,170
1,170/52=22.5/25=0.90