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uranmaximum [27]

3 years ago

14

A pigeon leaves its nest and flies 5 km due east. The pigeon then flies 3 km due north. How far away is the pigeon from its nest

? Round to one place after the decimal.

1 answer:

Nadusha1986 [10]3 years ago

3 0

Answer:

I got 8 but check

Step-by-step explanation:

i rounded the off and then added them that's what I learned to do

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adoni [48]

4 is again c because you should put the 2 here 2a'2-1 so this is 2a'1 and this is 20 so
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3 years ago

5x-4y-6z = -3<br> X-3y+z=-1<br> -3x-6y+7z=1

PilotLPTM [1.2K]

Answer:

$x=-\frac{41}{55},y=\frac{2}{55},z=-\frac{8}{55}$

Step-by-step explanation:

$5x-4y-6z=-3...............eq(1)\\\\x-3y+z=-1.....................eq(2)\\\\-3x-6y+7z=1.................eq(3)$

$eq(1)-5\times eq(2)$

$5x-4y-6z-5(x-3y+z)=-3-5\times (-1)\\\\11y-11z=2\\\\y-z=\frac{2}{11}...................eq(4)$

$3\times eq(2)+eq(3)$

$3(x-3y+z)-3x-6y+7z=3\times (-1)+1\\\\-15y+10z=-2\\\\-y+\frac{2}{3}z=-\frac{2}{15}.........eq(5)$

$eq(4)+eq(5)$

$y-z-y+\frac{2}{3}z=\frac{2}{11}-\frac{2}{15}\\\\-\frac{1}{3}z=\frac{8}{165}\\\\z=-\frac{8\times 3}{165}\\\\z=-\frac{8}{55}$

From $eq(4)$

$y=z+\frac{2}{11}=-\frac{8}{55}+\frac{2}{11}\\\\y=\frac{2}{55}$

Substitute the value of $y$ and $z$ in $eq(2)$

$x-3\times \frac{2}{55}-\frac{8}{55}=-1\\\\x-\frac{14}{55}=-1\\\\x=-1+\frac{14}{55}\\\\x=\frac{41}{55}$

6 0

4 years ago

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Brilliant_brown [7]

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Step-by-step explanation:

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3 years ago

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Step-by-step explanation:

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3 years ago