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olga_2 [115]
3 years ago
14

Which lines or segments are parallel based off markings?

Mathematics
1 answer:
liberstina [14]3 years ago
7 0
AD BC are parallel because the lines are equal
You might be interested in
Could someone help with the questions in the images below? I found them difficult
zubka84 [21]
Question 1a - You have got this correct, the median mark is 35
Question 1b- To work out the range, you must do the largest value subtract the smallest value. For your data, this would be 57 - 13 = 44

Question 2 - You have drawn the lines in the correct places, but you have not used a ruler. In order to get full marks on a question like this you must use a ruler.

Question 3 - Your lower quartile and median is correct, to find the upper quartile, we do 3(n/4). 'n' is the number of data points - in this case 120.
120/4 = 30
30 x 3 = 90
Go across the graph at 90 to see when the line is hit.
From what I can tell, the Upper Quartile is 3.

Next just find the maximum value.
Again, by the looks of it, the Maximum value is 8.5.

Now you have all the data needed for the box plot.

Min = 0
LQ = 0.8
Med = 2.1
UQ =  3
Max = 8.5

Using this information, draw a box plot like you did on the previous question.
<em>Again, I must stress that any line that you draw (unless purposely curved) must be drawn with a ruler; even on the graph at the top, during you working out. If you do not use a ruler, marks can be lost/taken away.</em>

Question 4a - For the median on a cumulative frequency chart, you must find the halfway point in the data. For this, we do n/2. In this case, n = 40
40/2 = 20
Draw a line (using  ruler) across at 20 until you reach the line.
Draw another one down to help you read the number.
The median looks like 34 seconds.
Question 4b - For this question, we already know the Min, Med and Max. Now we must work out the LQ and UQ.

Remember, LQ = n/4
In this case, n = 40
40/4 = 10
Look across at ten and you will find that the LQ = 16 seconds

To work out the UQ, we multiply the LQ place by 3 3(n/4).
3 x 10 = 30
30 on the graph takes us up to 45 seconds.

We now know that the:
Min = 9
LQ = 16
Med = 34
UQ = 45
Max = 57

With this information, draw a box plot like you have in the previous questions.

Question 5 - Good things to always compare on box plots are the Min/Max/Range and the Inter Quartile Range.
The boys had a lowest minimum and a higher maximum, this means that their range is larger, resulting in a large spread of data in comparison to the girls.
The Inter Quartile Range is the difference between the Upper Quartile and the Lower Quartile (how wide the box is).
The boy IQR = 45 - 16 = 29
The girls IQR = 34 - 23 = 11
Again, the girls have much more concise results; even though they did not get the quickest result, they were more like one another.

Question 5a - The median in a box plot is always the line down the centre of the box. In this case:
Median = 24 marks
Question 5b - The IQR is always the UQ - LQ
With this data, the IQR is the following:
36 - 17 = 19 marks

Hope this helps
6 0
3 years ago
​Together, teammates Pedro and Ricky got 2673 base hits last season. Pedro had 277 more hits than Ricky. How many hits did each
ioda

Answer:

Pedro got 1520 base hits and Ricky got 1243.

Step-by-step explanation:

This question can be solved by a system of equations.

I am going to say that:

x is the number of base hits that Pedro got.

y is the number of base hits that Ricky got.

Pedro and Ricky got 2673 base hits last season.

This means that x + y = 2763

Pedro had 277 more hits than Ricky.

This means that x = y + 277

Replacing in the first equation

x + y = 2763

y + 277 + y = 2763

2y = 2486

y = \frac{2486}{2}

y = 1243

x = y + 277 = 1243 + 277 = 1520

Pedro got 1520 base hits and Ricky got 1243.

4 0
3 years ago
7j + 5 - 8k when j = 0.5 and k = 0.25
tekilochka [14]

Answer:

I have no clue

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Flying with the wind, a small plane flew 404 mi in 2 h. Flying against the wind, the plane could fly only 386 mi in the same amo
Alika [10]

Answer: rate of the plane is 197.5 mph

rate of wind is 4.5 mph

Step-by-step explanation:

Let x represent the rate of the plane in calm air.

Let y represent the rate of the wind.

Flying with the wind, a small plane flew 404 mi in 2 h. This means that the total speed with which the plane flew is (x + y) mph.

Distance = speed × time

Distance travelled by the plane while flying with the wind is

404 = 2(x + y)

Dividing both sides of the equation by 2, it becomes

202 = x + y- - - - - - - - - - - 1

Flying against the wind, the plane could fly only 386 mi in the same amount of time. This means that the total speed at which the plane flew is (x - y) mph.

Distance = speed × time

Distance travelled by the plane while flying against the wind is

386 = 2(x - y)

Dividing both sides of the equation by 2, it becomes

193 = x - y- - - - - - - - - - - 2

Adding equation 1 to equation 2, it becomes

395 = 2x

x = 395/2

x = 197.5

Substituting x = 197.5 into equation 1, it becomes

202 = 197.5 + y

y = 202 - 197.5

y = 4.5

3 0
3 years ago
Triangle ABC was rotated about the origin. Which rule
Nuetrik [128]
<h3>Answer: Choice A   R_0, 90^{\circ}</h3>

The R stands for "rotation". The "O" as a small subscript means "origin" which is where the x and y axis cross. The 90 degrees means we rotate 90 degrees counterclockwise. This is equivalent to 270 degrees clockwise, but writing R_0, 270^{\circ} is not correct as we don't rotate 270 degrees counterclockwise.

3 0
3 years ago
Read 2 more answers
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