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OLga [1]
4 years ago
11

What are all of the prime factors of 35?

Mathematics
1 answer:
neonofarm [45]4 years ago
5 0

Answer:

Well, the only prime factor of 35 would be 5 × 7.

Step-by-step explanation:

For addition, all of the number 35's divisors would be:

1, 5, 7, 35.

Which means, 5 and 7 are the only numbers that 35 can be divided to besides 1 and itself.

Hope this helps!

You might be interested in
List 3 values that would make this inequality true 24 < y + 7
Zanzabum
With this problem, subtract 7 from both sides to get

17< y

So any number that is greater than 17 is a value that would make it true....19, 24, 35, 100, 39,1028 

4 0
3 years ago
Read 2 more answers
What is the area, in square feet, of the shape below?
grin007 [14]

Answer:

17.4 ft²

Step-by-step explanation:

The formula to find the area of a triangle:

1/2 x b x h, where b is the base and h is the height.

1) Substitute the given values into the formula and solve it.

= 1/2 x 6 x 5.8

= 1/2 x 34.8

= 17.4

7 0
3 years ago
Read 2 more answers
Can anyone tell me why by direct substitution of x, the equation (circled ones) equals to the indeterminate form, 0/0? When you
Katena32 [7]

Answer:

See explanation and hopefully it answers your question.

Basically because the expression has a hole at x=3.

Step-by-step explanation:

Let h(x)=( x^2-k ) / ( hx-15 )

This function, h, has a hole in the curve at hx-15=0 if it also makes the numerator 0 for the same x value.

Solving for x in that equation:

Adding 15 on both sides:

hx=15

Dividing both sides by h:

x=15/h

For it be a hole, you also must have the numerator is zero at x=15/h.

x^2-k=0 at x=15/h gives:

(15/h)^2-k=0

225/h^2-k=0

k=225/h^2

So if we wanted to evaluate the following limit:

Lim x->15/h ( x^2-k ) / ( hx-15 )

Or

Lim x->15/h ( x^2-(225/h^2) ) / ( hx-15 ) you couldn't use direct substitution because of the hole at x=15/h.

We were ask to evaluate

Lim x->3 ( x^2-k ) / ( hx-15 )

Comparing the two limits h=5 and k=225/h^2=225/25=9.

3 0
3 years ago
What is 3/8 divided by 7/2
Soloha48 [4]

3/8 divided by 7/2

copy dot flip

3/8 * 2/7

6 /56

3/ 28

4 0
3 years ago
Tyler is offered to choose between three boxes that look identical. The first box contains 1 red pills and 19 blue pills, the se
Dafna1 [17]

Answer:

A) 0.15

B) 0.36

Step-by-step explanation:

First Box consist 1 red pills and 19 blue pills

second box consist 6 red pills and 14 blue pills

Third box consist 2 red pills and 18 blue pills

a) Prob ( randomly chosen pill is red) = \frac{1}{3} \times \frac{1}{20} + \frac{1}{3} \times \frac{6}{20} + \frac{1}{3} \times \frac{2}{20}

\frac{1}{60} (1+6+2) = 0.15

b)Prob ( 1 reds and 10 blue pilss) =\frac{1}{3} \frac{^1C_1\times ^{19}C_{10}}{^{20}C_{11}} + \frac{1}{3} \frac{^6C_1\times ^{14}C_{10}}{^{20}C_{11}} + \frac{1}{3} \frac{^2C_1\times ^{18}C_{10}}{^{20}C_{11}}

= \frac{1}{3} 1.106 = 0.368

7 0
3 years ago
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