Answer:
y = x/10 + 43/10
Step-by-step explanation:
y - y1/ x - x1 = y2 - y1/ x2 - x1
y - 4/ x +3 = 5 - 4/7 + 3
y - 4 / x + 3 = 1/10
10(y - 4) = x + 3
10y - 40 = x + 3
10y = x + 43
y = x/10 + 43/10
If h is m above the ocean and your trying to find when the rocket reaches that ocean… as the function gives the height above the ocean at a given time, when the height equals 0 the rocket will have reached the ocean so solve for t when h=0. working out in the photo. i got t=48.88seconds
A, because anything with a dilation will not be congruent as the original PQR :))
Answer:
P(orange)x P(orange)= 5/9 x 5/9= 25/81
Step-by-step explanation:
Then a is Half of 45 wich is 22.5 I believe.