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Ksju [112]
2 years ago
9

Please help!!!!!!!!!!!!

Mathematics
1 answer:
vladimir1956 [14]2 years ago
7 0

Answer:

use a calculator

Step-by-step explanation:

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Cole has 5 times as many pencils as
Nataly [62]

Answer:

Cole has 15 pencils.

Step-by-step explanation:

First, we have the equation c + o =18, c representing cole, and o representing connor.

From there, we get 5o=c

Using substitiution, we get o=3

5(3)=15

15+3=18

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2 years ago
How do I put these equations into vertex form?
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Which expression defines the given series for seven terms?<br><br> 15 + 19 + 23 + . . .
dolphi86 [110]
The expression defines the given series for seven terms, i don't understand the question but i do know the sum which you should know to 

15 + 19 + 23 = 57

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5 0
3 years ago
Read 2 more answers
A group of friends are playing a game in which they roll a number cubed numbered 1 to 6 and flip a coin. The friend that rolls t
Ghella [55]

Answer:

A. The probability is 1/12. B. The probability is 1/10

Step-by-step explanation:

8 0
3 years ago
The usher at a wedding asked each of the 808080 guests whether they were a friend of the bride or of the groom. Here are the res
malfutka [58]

<u>Complete Question</u>

The usher at a wedding asked each of the 80 guests whether they were a friend of the bride or of the groom. The results are: 59 for Bride, 50 for Groom, 30 for both. Find the probability that a randomly selected person from this sample was a friend of the bride OR of the groom.

Answer:

0.9875

Step-by-step explanation:

Total Number of Guests, n(S)=80

Let the Event (a friend of the bride) =B

Let the Event (a friend of the groom) =G

n(B) =59

n(G)=50

n(B \cap G)=30

Therefore:

n(B \cup G)=n(B)+n(G)-n(B \cap G)\\n(B \cup G)=59+50-30\\n(B \cup G)=79

Number of Guests who was a friend of the bride OR of the groom = 79

Therefore:

The probability that a randomly selected person from this sample was a friend of the bride OR of the groom.

P(B \cup G) =\dfrac{n(B \cup G) }{n(S)} \\\\=\dfrac{79 }{80}\\\\=0.9875

4 0
3 years ago
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