Find the area of the figure to the nearest tenth.

Mathematics

1 answer:

iris [78.8K]3 years ago

7 0

[tex]{6}^{2} ft - (3.14){3}^{2}(0.5) ft \\ = (36 - 1.57(9) )ft \\ = 21.9{ft}^{2}/tex]

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HELP ME IM TERRIBLE AT THIS

OLEGan [10]

Answer:

a. $14.50

b. $43.5

Step-by-step explanation:

a. $7.00 + $7.50 = $14.50

b. y = 14.5x x=3

y = $14.5 x 3 = $43.5

8 0

3 years ago

The scale on a map is 1 : 500000 <br> Two towns are 7cm apart on the map

KengaRu [80]

1 : 500,000

multiplied by 7 cm is

7 cm : 3,500,000 cm

= 7 cm : 35000.00 m . . . (100 cm in 1 m)

= 7 cm : 35 km . . . (1000 m in 1 km)

The actual distance between the towns is 35 km.

5 0

3 years ago

URGENT: If θ is a second-quadrant angle and cosθ = -2/3, then tanθ = _____.

dangina [55]

In the second quadrant, both cos and tan are negative while only sin is positive.

To find tan, we will use the following property below:

$\large \boxed{ {tan}^{2} \theta = {sec}^{2} \theta - 1}$

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$\large{ {tan}^{2} \theta = {( - \frac{3}{2}) }^{2} - 1} \\ \large{ {tan}^{2} \theta = \frac{9}{4} - 1} \\ \large{ {tan}^{2} \theta = \frac{9}{4} - \frac{4}{4} \longrightarrow \frac{5}{4} } \\ \large{tan \theta = \frac{ \sqrt{5} }{ \sqrt{4} } } \\ \large \boxed{tan \theta = \frac{ \sqrt{5} }{2} }$