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asambeis [7]
3 years ago
5

Find the area of the figure to the nearest tenth.

Mathematics
1 answer:
iris [78.8K]3 years ago
7 0

[tex]{6}^{2} ft - (3.14){3}^{2}(0.5) ft \\ = (36 - 1.57(9) )ft \\ = 21.9{ft}^{2}/tex]

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Find an explicit formula for the arithmetic sequence 12, 5, -2, -9,...<br> a(n)=
masha68 [24]

a is the beggining number and n is the amount of times needed to do this. if is   17 you would need to subtract 7 from the originol number 12 (a)  that many times.

3 0
3 years ago
Almost all medical schools in the United States require students to take the Medical College Admission Test (MCAT). To estimate
yKpoI14uk [10]

Answer:

a) 0.5588

b) 0.9984

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 24

Standard Deviation, σ = 6.4

We are given that the distribution of score is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}        

a) P(score between 20 and 30)

P(20 \leq x \leq 30) = P(\displaystyle\frac{20 - 24}{6.4} \leq z \leq \displaystyle\frac{30-24}{6.4}) = P(-0.62 \leq z \leq 0.94)\\\\= P(z \leq 0.94) - P(z < -0.62)\\= 0.8264 - 0.2676 = 0.5588 = 55.88\%

P(20 \leq x \leq 30) = 55.88\%

b) Sampling distribution

Sample size, n = 22

The sample will follow a normal distribution with mean 24 and standard deviation,

s = \dfrac{\sigma}{\sqrt{n}} = \dfrac{6.4}{\sqrt{22}} =1.36

c) P(mean score of sample is between 20 and 30)

P(20 \leq x \leq 30) = P(\displaystyle\frac{20 - 24}{1.36} \leq z \leq \displaystyle\frac{30-24}{1.36}) = P(-2.94 \leq z \leq 4.41)\\\\= P(z \leq 4.41) - P(z < -2.94)\\= 1 - 0.0016 = 0.9984 = 99.84\%

P(20 \leq x \leq 30) =99.84\%

5 0
4 years ago
Two sides of a triangle have lengths of 7 ft and 15 fr. Which inequality represents the possible length for the third side, x?
Inessa05 [86]

6 < c < 20,

Of course if you knew the triangle was a right triangle you could use the Pythagorean theorem to directly get the size of the third side.
3 0
3 years ago
What is the median of the second half of the data? $777, $498, $619, $379, $895, $1,256, $$1,052
Anna71 [15]

Answer:

Median: 379

Tho if it wrong Which half $777, $498, $619, $379, $895, $1,256, $1,052?

6 0
3 years ago
A warehouse distributor of carpet faces a normally distributed demand for its carpet. The average demand for carpet from the sto
Snezhnost [94]

Answer with Step-by-step explanation:

Since the demand is normally distributed the required probability can be found from the area under the normal distribution curve as

Part a)

Given mean = 4500 yards per month

Standard deviation = 900 yards

Thus area under the curve corresponding to 6000 yards is found from the standard variate factor Z as

Z=\frac{X-\bar{X}}{\sigma }\\\\Z=\frac{6000-4500}{900}=1.67

Area for Z = 1.67 = 95.22%

Thus the probability that the demand will be met is 0.9522 hence the probability that the demand will not be met is P(E)=1-0.9522=0.0478

Part b)

The reuired answer is area between 5000 and 7000 yards in the normal distribution curve thus we have

Z_1=\frac{5000-4500}{900}=0.56.

Z_2=\frac{7000-4500}{900}=2.78

The area between these 2 values is 49.73% hence the reuired probability is 0.4973.

Part c)

For 97% satisfaction of demand the Z factor corresponding to 97% of area is found to be 1.88

thus we can write

1.88=\frac{X-4500}{900}\\\\X=4500+1.88\times 1.88=6193

4 0
3 years ago
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