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2 years ago

10

(3x^2-29z+56) ÷(z-7)

1 answer:

ozzi2 years ago

3 0

Is this a multivariate function

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Find the solution set of this equation.<br> y^2-11y=0 <br> separate the two values with a comma.

Tanya [424]

Answer:

0,11

Step-by-step explanation:

y^2-11y=0

y(y-11)=0 we have transformed the equation into a product

a product can be zero only if one of the factors is 0

so the two solutions are

y=0

and y-11=0 y=11

6 0

2 years ago

It’s probably rlly simple I just dk how to do it :)

Helga [31]

Answer:

18,0

Step-by-step explanation:

By useing desmos, the line has an x intercept of 18 making that the answer.

8 0

2 years ago

Read 2 more answers

Easy question.<br><br> Solve the inequality -5x<40

laiz [17]

$\huge\text{Hey there!}$

$\mathsf{-5x < 40}$

$\large\text{DIVIDE -5 to BOTH SIDES}$

$\mathsf{\dfrac{-5x}{-5}$

$\rm{CANCEL\ out: \dfrac{-5}{-5} \ because\ that \ gives\ you\ 1}$

$\rm{KEEP: \dfrac{40}{-5}\ because \ that \ gives \ you \ what \ you \ are\ comparing}\\\\\rm{to \ the \ x-value}$

$\mathsf{\dfrac{40}{-5}=\boxed{\bf -8}}$

$\mathsf{x > -8}$

$\boxed{\boxed{\large\textsf{Answer: \large \bf x }\bf > \large\textsf{\bf -8}}}\huge\checkmark$

$\boxed{\large\textsf{IT is an O(P)(E)(N)(E)(D) circle shaded to the right}}$

$\large\text{Good luck on your assignment and enjoy your day!}$

~ $\frak{Amphitrite1040:)}$

3 0

2 years ago

Right triangle ABC is similar to right triangle DEF. If the side lengths for triangle ABC are 15, 20, 25, respectively, which va

solniwko [45]

Answer:

$A = 15$ $B = 20$ $C = 25$

$D = 30$ $E = 40$ $F = 50$

$D = 3$ $E = 4$ $F = 5$

Step-by-step explanation:

Given

Similar Triangles: ABC and DEF

$A = 15$

$B = 20$

$C = 25$

Required

Determine the sides of DEF

No options were given, so I will solve on a general terms.

Since both triangles are similar, then the following relationship exists.

DEF = ABC * n

i.e.

$D = A * n$ $E = B * n$ $F = C * n$

Where

$n = Scale\ Factor$

Assume n = 2.

So, we have:

$D = A * n$

$D =15 *2$

$D = 30$

$E = B * n$

$E = 20 * 2$

$E = 40$

$F = C * n$

$F = 25 * 2$

$F = 50$

Assume $n = \frac{1}{5}.$

So, we have:

$D = A * n$

$D =15 *\frac{1}{5}$

$D = 3$

$E = B * n$

$E = 20 * \frac{1}{5}$

$E = 4$

$F = C * n$

$F = 25 * \frac{1}{5}$

$F = 5$

So, the possible sides are:

$A = 15$ $B = 20$ $C = 25$

$D = 30$ $E = 40$ $F = 50$

$D = 3$ $E = 4$ $F = 5$

6 0

2 years ago

Use the grouping method to factor the polynomial below completely. x3 - 3x2 + 5x - 15

LUCKY_DIMON [66]

Answer:

(x²+5) (x-3)²

Step-by-step explanation:

x³ - 3x² + 5x - 15

x²(x-3) + 5(x-3)

(x²+5) (x-3)²

4 0

2 years ago