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2 years ago

Will mark brainliest please help , worth 30 points need answers too both

Mathematics

1 answer:

Yanka [14]2 years ago

7 0

(18)

2.5% of 129,500 is

$129500 * 0.025 = $3237.50 is the commission on the sale

(19)

sales $3012

commission 3.5% of sales: 0.035 * 3012 = $105.42

Raquelle's total earnings: $290 + 105.42 = $395.42

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Find the measure of the missing angle <br><br> Help please

almond37 [142]

Answer:

≈ 56°

Step-by-step explanation:

Using the sine ratio in the right triangle

sin ? = $\frac{opposite}{hypotenuse}$ = $\frac{34}{41}$ , then

? = $sin^{-1}$ ( $\frac{34}{41}$ ) ≈ 56° ( to the nearest degree )

7 0

3 years ago

3. A driver's path when diving off of a platform is given by h(t)=-5t^2+10t+20, where h(t) is the distance above water, in feet,

agasfer [191]

Answer:

3a.=20ft 3b.=1 second 3c.=3.25seconds

Step-by-step explanation:

Hello, Courtney!

h(t)=-5t^2+10t+20

20 would be the height so 3.a would be 20ft

3b. 25=-5t^2+10t+20

-5t^2+10t-5 then divide by greatest factor the answer would 1 second

3c. 0=-5t^2+10t+20 divide by greatest factor and would get 3.25 and -1.25 but can't have negative so the answer is 3.25.

I hope this helps

best you know who!

5 0

2 years ago

labwork [276]

Answer:

no 379s not in the sequence below

6 0

2 years ago

In general, the probability that a blood donor has Type A blood is 0.40.Consider 8 randomly chosen blood donors, what is the pro

postnew [5]

Answer:

The probability that more than half of them have Type A blood in the sample of 8 randomly chosen donors is P(X>4)=0.1738.

Step-by-step explanation:

This can be modeled as a binomial random variable with n=8 and p=0.4.

The probability that k individuals in the sample have Type A blood can be calculated as:

$P(x=k) = \dbinom{n}{k} p^{k}(1-p)^{n-k}\\\\\\P(x=k) = \dbinom{8}{k} 0.4^{k} 0.6^{8-k}\\\\\\$

Then, we can calculate the probability that more than 8/2=4 have Type A blood as:

$P(X>4)=P(X=5)+P(X=6)+P(X=7)+P(X=8)\\\\\\P(x=5) = \dbinom{8}{5} p^{5}(1-p)^{3}=56*0.0102*0.216=0.1239\\\\\\P(x=6) = \dbinom{8}{6} p^{6}(1-p)^{2}=28*0.0041*0.36=0.0413\\\\\\P(x=7) = \dbinom{8}{7} p^{7}(1-p)^{1}=8*0.0016*0.6=0.0079\\\\\\P(x=8) = \dbinom{8}{8} p^{8}(1-p)^{0}=1*0.0007*1=0.0007\\\\\\\\P(X>4)=0.1239+0.0413+0.0079+0.0007=0.1738$

3 0

3 years ago

I don’t understand how to do it ?

Temka [501]

We know that Sum of Angles in a Triangle is Equal to 180°

Here EBF is a Triangle

⇒ m∠EBF + m∠BEF + m∠EFB = 180°

⇒ 60° + 40° + m∠EFB = 180°

⇒ 100° + m∠EFB = 180°

⇒ m∠EFB = 180° - 100°

⇒ m∠EFB = 80°

As Line m and Line p are Parallel Lines :

Alternate Interior Angles are Equal, here Alternate Interior Angles are m∠BEF and m∠ABE

⇒ m∠BEF = m∠ABE

⇒ m∠ABE = 40°

We know that Vertically Opposite Angles are Equal, Here m∠GFI and m∠EFB are Vertically Opposite Angles.

⇒ m∠GFI = m∠EFB

⇒ m∠GFI = 80°

We can notice that m∠DEB and m∠BEF form a Linear Pair

⇒ m∠DEB + m∠BEF = 180°

⇒ m∠DEB + 40° = 180°

⇒ m∠DEB = 180° - 40°

⇒ m∠DEB = 140°

We can notice that Sum of Angles m∠CBF and m∠EBF and m∠ABE is 180°

⇒ m∠CBF + m∠EBF + m∠ABE = 180°

⇒ m∠CBF + 60° + 40° = 180°

⇒ m∠CBF + 100° = 180°

⇒ m∠CBF = 180° - 100°

⇒ m∠CBF = 80°

We can notice that m∠BFG and m∠EFB form a Linear Pair

⇒ m∠BFG + m∠EFB = 180°

⇒ m∠BFG + 80° = 180°

⇒ m∠BFG = 180° - 80°

⇒ m∠BFG = 100°

We know that Vertically Opposite Angles are Equal, Here m∠BFG and m∠IFE are Vertically Opposite Angles.

⇒ m∠BFG = m∠IFE

⇒ m∠IFE = 100°

3 0

3 years ago