Mila has a loyalty card good for a discount at her local grocery store. The item she wants to buy is priced at $10, before disco
2 answers:
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Answer:
one large box equals 15.75<em>kg</em>
one small box equals 13.75<em>kg</em>
Step-by-step explanation:
First, identify your variables:
Let "l" represent the weight of one large box.
Let"s" represent the weight of one small box.
Then, stack the two equations on top of each other:
Next, multiply the first equation by 3 so we can use elimination of the "s" variable to find the "l" variable first:
Now, subtract the two equations to cancel out the s-variable and find the l-variable:
Then, substitute your l-variable in the original first equation to find the s-variable:
With all the information that is collected, you find that one large box weighs 15.75<em>kg</em> and one small box weighs 13.75<em>kg</em>.
Answer:
Hey, Dalilah. I hope I'm not too late, but the answer is <u><em>(3,5)</em></u>.
Step-by-step explanation:
You have to use the equation that includes the x value of <em>3</em>.
<em>4x+1</em> only includes x values that are less than <em>3</em>.
<em>2x-1</em> includes x values that are greater than or equal to <em>3</em>.
I plugged <em>3</em> into both of these equations <em>(4x+1; x < 3 & 2x-1; x ≥ 3)</em> in order to see which equation would've been true.
<em>4(3)+1 = 13; 13 < 3 [False] 13 isn't less than 3 -- and 2(3)-1 = 5; 5 ≥ 3 [True] 5 is greater than or equal to 3.</em>
Since the equation <em>2(3)-1; 5≥3</em> is true, you should use this equation. I used <em>Demos</em> in order to graph <em>Y=2(3)-1</em>. At the bottom of that I put <em>x=3</em>, and it showed me <em>(3,5)</em>.
I'll post the pictures for proof and better clarification if this is confusing, love.
