Answer:
3.s is 3 times the age of Sydney's which is equals to Luke age + 5
Step-by-step explanation:
Given Sydney’s age, s
and also Luke is 5 years younger than 3 times Sydney’s age.
Sydney's 3 times age is 3.s
Luke age = Sydney's 3 times age - 5
Luke age=3.s-5 ⇒ 3.s = Luke age + 5
Hence, 3.s is 3 times the age of Sydney's which is equals to Luke age + 5
Puting it into the quadrait equation ((-b+-[b^2-4ac]^(1/2)/2a), we get that x= 31^(1/2)-5 or 31^(1/2)+5
Answer:
The answer is a. 21.
Step-by-step explanation:
We solve this question by using Pythagoras theorem to relate the sides of a right angled triangle.
Here,
Hypotenuse of the given triangle(c)=75
Two sides of right angled triangle are:
a=72
b=?
Then,
for a given right angled triangle abc,
Using Pythagoras theorem,

Squaring on both sides,

or,
or, 
or,
or,
∴
So, the value of b is obtained to 21 by the use of Pythagoras theorem.
Hello Hdolly81
<u><em>The LCM of 156 and 321 is 16692</em></u>
Backup:
156: 2,2,3,13,
321: 3,107
2 * 2 * 3 * 13 * 107 = 16692
:)