-17 would be the answer to this problem
Answer:
The bearing needed to navigate from island B to island C is approximately 38.213º.
Step-by-step explanation:
The geometrical diagram representing the statement is introduced below as attachment, and from Trigonometry we determine that bearing needed to navigate from island B to C by the Cosine Law:
(1)
Where:
- The distance from A to C, measured in miles.
- The distance from A to B, measured in miles.
- The distance from B to C, measured in miles.
- Bearing from island B to island C, measured in sexagesimal degrees.
Then, we clear the bearing angle within the equation:
(2)
If we know that 
, 
, 
, then the bearing from island B to island C:
![\theta = \cos^{-1}\left[\frac{(7\mi)^{2}+(8\,mi)^{2}-(5\,mi)^{2}}{2\cdot (8\,mi)\cdot (7\,mi)} \right]](https://tex.z-dn.net/?f=%5Ctheta%20%3D%20%5Ccos%5E%7B-1%7D%5Cleft%5B%5Cfrac%7B%287%5Cmi%29%5E%7B2%7D%2B%288%5C%2Cmi%29%5E%7B2%7D-%285%5C%2Cmi%29%5E%7B2%7D%7D%7B2%5Ccdot%20%288%5C%2Cmi%29%5Ccdot%20%287%5C%2Cmi%29%7D%20%5Cright%5D)
The bearing needed to navigate from island B to island C is approximately 38.213º.
The first answer of the missing blank is 4/5.
The second answer of the missing blank is 2.
The third answer of the missing blank is 25.
*For all of these solutions, I will be using the common rules for logarithms.*
Solution for the first question:
Log9^4/5 must equal log9^4-log9^5, or it could also equal the more proper version, which is simplified: 2log9^2-log9^5.
Solution for the second question:
Log3^22 must equal log3^11+log3^2, if you break it down.
Solution for the third question:
Log9^25 must equal 2log9^5 because it will be like this when simplifying it:
log9^25=2log9^5
log9^5²=2log9^5
2log9^5=2log9^5
These are all of the step-by-step procedures for all three of these given questions. Anyways, I hope that this helped you!
Answer:
The = sign
Step-by-step explanation:
1 11/20 = 31/20 = 1.55 and 1.55 =1.55
