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4 years ago

PLEASE HELP!

Mathematics

2 answers:

algol [13]4 years ago

5 0

73 that will be hope this is right ok byeeee

vazorg [7]4 years ago

4 0

Here is how i figured it out. Good luck and i hope you understood my working

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A. Alternate exterior angles

tresset_1 [31]

Answer:

Step-by-step explanation:

Supplementary = 180 degrees aka straight line

3 0

3 years ago

Use the compound interest formula A =P(1 + r) t and the given information to solve for r.

Dmitry [639]

Answer:

Rounding to nearest hundredths gives us r=0.06.

So r is about 6%.

Step-by-step explanation:

So we are given:

$A=P(1+r)^t$

where

$A=2300$

$P=1600$

$t=6$ .

$A=P(1+r)^t$

$2300=1600(1+r)^6$

Divide both sides by 1600:

$\frac{2300}{1600}=(1+r)^6$

Simplify:

$\frac{23}{16}=(1+r)^6$

Take the 6th root of both sides:

$\sqrt[6]{\frac{23}{16}}=1+r$

Subtract 1 on both sides:

$\sqrt[6]{\frac{23}{16}}-1=r$

So the exact solution is $r=\sqrt[6]{\frac{23}{16}}-1$

Most likely we are asked to round to a certain place value.

I'm going to put my value for r into my calculator.

r=0.062350864

Rounding to nearest hundredths gives us r=0.06.

8 0

4 years ago

What is the product?

Tanzania [10]

Answer:

$=\begin{pmatrix}-5&6\\ 1&-4\end{pmatrix}$

Step-by-step explanation:

$\begin{pmatrix}-3&4\\2&-5\end{pmatrix}\begin{pmatrix}3&-2\\ 1&0\end{pmatrix}$

Multiply the row of the first matrix to the column of the second matrix

$\begin{pmatrix}-3&4\end{pmatrix}\begin{pmatrix}3\\ 1\end{pmatrix}=\left(-3\right)\cdot \:3+4\cdot \:1$

$\begin{pmatrix}-3&4\end{pmatrix}\begin{pmatrix}-2\\ 0\end{pmatrix}=\left(-3\right)\left(-2\right)+4\cdot \:0$

$\begin{pmatrix}2&-5\end{pmatrix}\begin{pmatrix}3\\ 1\end{pmatrix}=2\cdot \:3+\left(-5\right)\cdot \:1\$

$\begin{pmatrix}2&-5\end{pmatrix}\begin{pmatrix}-2\\ 0\end{pmatrix}=2\left(-2\right)+\left(-5\right)\cdot \:0\$

$=\begin{pmatrix}\left(-3\right)\cdot \:3+4\cdot \:1&\left(-3\right)\left(-2\right)+4\cdot \:0\\ 2\cdot \:3+\left(-5\right)\cdot \:1&2\left(-2\right)+\left(-5\right)\cdot \:0\end{pmatrix}$

simplifying them we get

$=\begin{pmatrix}-5&6\\ 1&-4\end{pmatrix}$

8 0

3 years ago

The roots of the equation are 3 + 8i and 3 – 8i.

g100num [7]

Given that the roots of the equation x^2-6x+c=0 are 3+8i and 3-8i, the value of c can be obtained as follows;
taking x=3+8i and substituting it in our equation we get:
(3+8i)^2-6(3+8i)+c=0
-55+48i-18-48i+c=0
collecting the like terms we get:
-55-18+48i-48i+c=0
-73+c=0
c=73
the answer is c=73

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3 years ago

The length of a quarter is 0.955 inch. Round the length of a quarter to the nearest tenth of an inch./8925047/32fb89d7?utm_sourc

m_a_m_a [10]

0.2387528472385828522

7 0

3 years ago