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belka [17]
2 years ago
15

Write the equation that is the translation of y= |x| right 7 units and down 9 units.

Mathematics
2 answers:
CaHeK987 [17]2 years ago
8 0
The answer is D. When is says a translation right you have to subtract that number (a translation left means you have to add) and when you translate the equation down, you subtract.
kow [346]2 years ago
7 0

f(x) + n - translation n units up

f(x) - n - translation n units down

f(x + n) - translation n units left

f(x - n) - translation n units right

translation 7 units right and 9 units down

f(x - 7) - 9 = |x - 7| - 9

Answer: D. y = |x - 7| - 9

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3x + 3y =15 and x = -3y -1
saul85 [17]

Answer:

  (x, y) = (8, -3)

Step-by-step explanation:

You can substitute for x in the first equation:

  3(-3y -1) +3y = 15

  -6y = 18 . . . . . add 3 and simplify

  y = -3 . . . . . . . divide by -6

  x = -3(-3) -1 = 8 . . . . find x using the second equation

The solution to this system of equations is (x, y) = (8, -3).

4 0
2 years ago
Simplify by combining like terms. <br> 12+5t−4+15t+1
quester [9]

Answer:

9+20t

Step-by-step explanation:

Look at the terms and see which has t and which is a number when you see like terms, add them or subtract them together to get like terms.

5 0
3 years ago
Based on a study of population projections for 2000 to​ 2050, the projected population of a group of people​ (in millions) can b
Olegator [25]

Answer:

(a) 0.107 million per year

(b) 0.114 million per year

Step-by-step explanation:

A(t) = 11.19(1.009)^t

(a) The average rate of change between 2000 and 2014 is determined by dividing the difference in the populations in the two years by the number of years. In the year 2000, t=0 and in 2014, t=14. Mathematically,

\text{Rate}=\dfrac{A(2014) - A(2000)}{2014-2000}=\dfrac{11.19(1.009)^14-11.19(1.009)^0} {14}

A(0)=\dfrac{12.69-11.19}{14}=\dfrac{1.5}{14}=0.107

(b) The instantaneous rate of change is determined by finding the differential derivative at that year.

The result of differentiating functions of the firm y=a^x (where a is a constant) is \dfrac{dy}{dx}=a^x\ln a. Let's use in this in finding the derivative of A(t).

A\prime(t) = \dfrac{A}{t}=11.19\cdot1.009^t\ln1.009

In the year 2014, t=14.

A\prime(14) =11.19\cdot1.009^14\ln1.009=0.114

6 0
3 years ago
Which of these properties is enough to prove that a given parallelogram is also a Rectangle?
lozanna [386]

we are supposed to find

Which of these properties is enough to prove that a given parallelogram is also a Rectangle?

As we know from the theorem, if the diagonals of a parallelogram are congruent then the parallelogram is a rectangle.

The other options The diagonals bisect each other is not sufficient because in parallelogram diagonals always gets bisected , parallelogram becomes rectangles only if both the diagonals are of same length.

In a parallelogram The opposite angles and opposite sides are always equal.

Hence the correct option is

The diagonals are congruent.

3 0
3 years ago
Read 2 more answers
Please help me to solve it
Phantasy [73]

What are you trying to solve for?

4 0
2 years ago
Read 2 more answers
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