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Stells [14]
3 years ago
15

Is y=2^x linear, exponential or neither

Mathematics
1 answer:
stepladder [879]3 years ago
3 0
Answer:
exponential

Step-by-step explanation:
An exponential function is defined as a function with a positive constant other than 1 raised to a variable exponent. A function is evaluated by solving at a specific input value. An exponential model can be found when the growth rate and initial value are known.

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A 750ml bottle of highland.Spring Water cost $0.96.Work out the cost per litre when bought in this way
iris [78.8K]

Answer:

$1.28 per liter

Step-by-step explanation:

750ml/1 L = .75

.96/.75 = 1.28

5 0
3 years ago
A drawer contains 8 blue socks, 8 black socks, and 4 white socks. Socks are picked at random. Explain why the events picking a b
sertanlavr [38]

Answer:

because he just wants his socks to wear

Step-by-step explanation:

8 0
3 years ago
What is m2?<br> What is m&lt;1?
yuradex [85]

Answer:

∠ 2 = 75° , ∠ 1 = 105°

Step-by-step explanation:

∠ 2 and 75° are alternate angles and are congruent , then

∠ 2 = 75°

∠ 1 and ∠ 2 are a linear pair and sum to 180° , that is

∠ 1 + ∠ 2 = 180°

∠ 1 + 75° = 180° ( subtract 75° from both sides )

∠ 1 = 105°

3 0
2 years ago
I really need help!! God bless you.
Nastasia [14]
Ok so 65 percent of 10,000 is 6500. This means that she has to get the other 3500 herself. Since she has a year to save divide 3500 by 12 for each month of the year which is equal to $291.67. Then simply round up to get your answer which is A. $292.

Hope this helped and good luck
3 0
3 years ago
Find the x-coordinates of any relative extrema and inflection point(s) for the function f(x)= 6x^1/3 + 3x^4/3. You must justify
irina [24]

Answer:

x-coordinates of relative extrema = \frac{-1}{2}

x-coordinates of the inflexion points are 0, 1

Step-by-step explanation:

f(x)=6x^{\frac{1}{3}}+3x^{\frac{4}{3}}

Differentiate with respect to x

f'(x)=6\left ( \frac{1}{3} \right )x^{\frac{-2}{3}}+3\left ( \frac{4}{3} \right )x^{\frac{1}{3}}=\frac{2}{x^{\frac{2}{3}}}+4x^{\frac{1}{3}}

f'(x)=0\Rightarrow \frac{2}{x^{\frac{2}{3}}}+4x^{\frac{1}{3}}=0\Rightarrow x=\frac{-1}{2}

Differentiate f'(x) with respect to x

f''(x)=2\left ( \frac{-2}{3} \right )x^{\frac{-5}{3}}+\frac{4}{3}x^{\frac{-2}{3}}=\frac{-4x^{\frac{2}{3}}+4x^{\frac{5}{3}}}{3x^{\frac{2}{3}}x^{\frac{5}{3}}}\\f''(x)=0\Rightarrow \frac{-4x^{\frac{2}{3}}+4x^{\frac{5}{3}}}{3x^{\frac{2}{3}}x^{\frac{5}{3}}}=0\Rightarrow x=1

At x = \frac{-1}{2},

f''\left ( \frac{-1}{2} \right )=\frac{4\left ( -1+4\left ( \frac{-1}{2} \right ) \right )}{3\left ( \frac{-1}{2} \right )^{\frac{5}{3}}}>0

We know that if f''(a)>0 then x = a is a point of minima.

So, x=\frac{-1}{2} is a point of minima.

For inflexion points:

Inflexion points are the points at which f''(x) = 0 or f''(x) is not defined.

So, x-coordinates of the inflexion points are 0, 1

7 0
3 years ago
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