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Umnica [9.8K]
3 years ago
5

The time T that technician requires to perform preventive maintenance on an air conditioning unit has an unknown probability dis

tribution. However, its mean is known to be 2 hours, with standard deviation 1 hour. Suppose the company maintains 70 of these units and that the conditions of the Central Limit Theorem apply. What is the probability that a maintenance operation will take more than 2 hours and 15 minutes?
Mathematics
1 answer:
fiasKO [112]3 years ago
6 0

Answer:

0.4

Step-by-step explanation:

To calculate the probability that a maintenance operation will take more than 2 hours and 15 minutes. We can first calculate the probability that ALL maintenance operation on 70 of the units will take less than 2 hours and 15 minutes, then subtract it from 1.

So the probability of a maintenance operation that would take less than 2 hours and 15 minutes, or 135 minutes is:

P(X \leq 135, \mu = 120, \sigma = 60) = 0.6

So the probability that a maintenance operation will take more than 2 hours and 15 minutes is:

1 - 0.6 = 0.4

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Place the dot at 11 and make it go to the right make sure the dot is full not open. Solution is x \geq 11

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The measure of angle A in ABC is twice the measure of angle B and the measure of angle C is 20° less than the measure
diamong [38]

Answer:

m∡A = 100°

m∡B = 50°

m∡C = 30°

Step-by-step explanation:

let 'x' = m∡B;  50°

let '2x' = m∡A;   100°

let 'x-20' = m∡C;   30°

x + 2x + x - 20 = 180

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7 0
3 years ago
Below are the jersey numbers of 11 players randomly selected from a football team. Find the​ range, variance, and standard devia
padilas [110]

Answer:

Option(A) is correct

Jersey numbers are nominal data that are just replacements for names, so the resulting statistics are meaningless.

Step-by-step explanation:

The given data set in the question are ;33, 29, 97, 56, 26, 78, 83, 74, 65, 47, 58

the range can be determined by finding the highest value and subtract it to the lowest value. In this case the values are:

Highest = 97

Lowest = 71

Range = highest value - Minimum value

Range = 97 - 26 = 71

Range= 71

mean of the data is the summation of all the numbers in the data set divided by the number of given samples.

Mean = (33 + 29 + 97 + 56+ 26 + 78 + 83 74+ 65 + 47 + 58)/11

= 647/11

Mean value =58.7

Now to find the variance of the data set by using below formular

σ²=[ (xᵢ -mean)²]/n-1

[(33-58.7)² +(29-58.7)²+( 97-58.7)²+( 56-58.7)²+( 26 -58.7)²+(78-58.7)²+( 83 -58.7)²+(74-58.7)²+( 65-58.7)²+( 47 -58.7)²+(58 -58.7)²]/10

Variance=546

Now, we will calculate standard deviation by taking square root over variance

σ =√(variance)

σ =√(546)

Standard deviation= 23.4

Hence, the range is 71 ,variance is 546 and standard deviation is 23.4 therefore,

Option A is the answer that is Jersey numbers are nominal data that are just replacements for names, so the resulting statistics are meaningless.

5 0
3 years ago
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