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3 years ago

10) Planteen la operación y resuelvan: El producto entre el cuadrado de -7 y la raíz cubica de 1728, todo eso sumado 14.

Mathematics

1 answer:

Firlakuza [10]3 years ago

4 0

Answer:

(-7)^2*∛(1728) + 14 = 49*12 + 14 = 588 + 14 = 602

Step-by-step explanation:

Primero definamos las operaciones usadas:

El cuadrado de un número N, se escribe como N^2

La raíz cubica de un número M, se escribe como ∛(M)

El producto entre dos números, A y B, se escribe como A*B

Ahora queremos plantear la operación:

"El producto entre el cuadrado de -7 y la raíz cubica de 1728, todo eso sumado 14."

Lo podemos separar en partes:

"El producto entre el cuadrado de -7 y la raíz cubica de 1728,..."

esto se escribe como:

(-7)^2*∛(1728)

Ahora, la operacion completa es:

El producto entre el cuadrado de -7 y la raíz cubica de 1728, todo eso sumado 14.

Esto se escribe como:

(-7)^2*∛(1728) + 14

Ahora debemos resolver esta operación.

sabemos que:

(-7)^2 = 49

∛(1728) = 12

Reemplazando esos dos en nuestra operación, obtenemos:

(-7)^2*∛(1728) + 14 = 49*12 + 14 = 588 + 14 = 602

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3 years ago

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3 years ago

Read 2 more answers

A quadratic equation is shown below: 3x^2 − 15x + 20 = 0 Part A: Describe the solution(s) to the equation by just determining th

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These are two questions and two answers:

Question 1:

<span>A quadratic equation is shown below: 3x^2 − 15x + 20 = 0 Part A: Describe the solution(s) to the equation by just determining the radicand. Show your work.

Answer: </span><span>The negative value of the radicand means that the equation does not have real solutions.

Explanation:

1) With radicand the statement means the disciminant of the quadratic function.

2) The discriminant is: b² - 4ac, where a, b, and c are the coefficients of the quadratic equation: ax² + bx + c

3) Then, for 3x² - 15x + 20, a = 3, b = - 15, and c = 20

and the discriminant (radicand) is: (-15)² - 4(3)(20) = 225 - 240 = - 15.

4) The negative value of the radicand means that the equation does not have real solutions.

Question 2:

Part B: Solve 3x^2 + 5x − 8 = 0 by using an appropriate method. Show the steps of your work, and explain why you chose the method used.

Answer: </span> two solutions x = 1 and x = - 8/3x

Explanation:

1) I choose factoring (you may use the quadratic formula if you prefer)

2) Factoring

Given: 3x² + 5x − 8 = 0

Make 5x = 8x - 3x: 3x² + 8x - 3x - 8 = 0

Group: (3x² - 3x) + (8x - 8) = 0

Common factors for each group: 3x(x -1) + 8(x - 1) = 0

Coomon factor x - 1: (x - 1) (3x + 8) = 0

The two solutions are for each factor equal to zero:

x - 1 = 0 ⇒ x = 1
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Those are the two solutions. x = 1 and x = - 8/3

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