The formula for surface area is SA = 2 (wl + hl + hw). Plugging in the numbers that we know, we get SA = 2 (100 + 10h +10h). We know that the crust accounts for half of the surface area.
The surface area was not provided so this is the closest I can go without the provided surface area. I hope this helps you :)
Answer:
SAS
Step-by-step explanation:
We can automatically eliminate the HL answer choice, since the given triangles aren't right triangles. The only answer choices that could make sense would be ASA or SAS, but there is no ASA choice, so the answer would be SAS.
Answer:
304m^2
Step-by-step explanation:
First find the surface area of the base by multiplying the length by the width.
(12m) (8m)= 96m^2
Second, find the surface area of the front and back triangles using the formula <em>1/2 (base) (height)</em>. Use the length for the base.
1/2 (12m) (10m)= 60m^2
Next, find the surface area of the side triangles using the formula <em>1/2 (base) (height). </em>Use the width as the base.
1/2 (8m) (11m)= 44m^2
Last, add the surface area of each section. Make sure you add the area of each face.(we only solved for 1 of the front/ back triangles and 1 of the side triangles) To make it easier to understand I wrote out an equation to show how I added the surface areas.
base=a, front/ back triangles= b, side triangles=c
SA= a + 2b +2c or SA= a +b +b +c +c
Using one of the equations above solve for the total surface area.
SA= (96m^2) + (60m^2) +(60m^2) +(44m^2) +(44m^2)
or
SA= (96m^2) + 2(60m^2) +2(44m^2)
SA= (96m^2) +(120m^2) +(88m^2)
SA= 304m^2
Answer:
Step-by-step explanation:
If the <em>angle of elevation</em> is congruent in both triangles, then both smaller legs are congruent.
I am joyous to assist you at any time.
