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Lostsunrise [7]
3 years ago
9

Given: P is a point on the perpendicular bisector, I of MN. Prove: PM = PN

Mathematics
1 answer:
Hatshy [7]3 years ago
5 0

Answer:

Step-by-step explanation:

I can't make specific statements about the proof because the midpoint is missing.

Givens

There are two right angles created by where the perpendicular bisector meats MN. Both are 90 degrees.

MN is bisected by the point on MN where the perpendicular meets MN

The Perpendicular Bisector is is common to both triangles.

Therefore the two triangles are congruent by SAS

PM = PN                Parts contained in Congruent triangles are congruent.

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The volume of this cylinder is 1,909.92384 cubic millimeters. What is the radius? Use n=3.14 and round your answer to the neares
klemol [59]

Remember that the volume of a cylinder is

\begin{gathered} V=\pi\cdot r^2\cdot h \\  \end{gathered}

so we have that

r=\sqrt[]{\frac{V}{\pi\cdot h}}=\sqrt[]{\frac{1909.92384}{3.14\cdot6.6}}=\sqrt[]{92.12}=9.6

so the radius is 9.6 milimeters

6 0
1 year ago
The radius of the circular track was 157.64 feet find the circumference of the track
DerKrebs [107]
Before we solve for anything, let's remember what our formula is.

The circumference of a circle is 2PiR (2 x Pi x R).

Our radius is 157.64.
Pi is 3.14 (estimated).

Let's plug our numbers into the formula.

Circumference = 2 x 3.14 x 157.64.
2 x 3.14 = 6.28
6.28 x 157.64 = 989.979 (990 if estimated).

Your circumference is:
989.979 ft^2.

I hope this helps!
7 0
3 years ago
This is a word problem: You are riding a ski lift at a position 57 feet off the ground. You spot one of your friends skiing belo
Varvara68 [4.7K]

Answer:6 minutes

Step-by-step explanation:

6 0
3 years ago
Write a corresponding real-world problem for each equation.
Kamila [148]

Answer:

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Step-by-step explanation:

6 0
3 years ago
The digits 4 comma 5 comma 6 comma 7 comma and 8 are randomly arranged to form a​ three-digit number. ​ (Digits are not​ repeate
fenix001 [56]

Answer:

0.1 or 1/10

Step-by-step explanation:

The digits 4, 5, 6, 7 and 8 are randomly arranged to form a three digit number, where the digits are not repeated.

This is question of permutation.

Imagine this sum as; there are 3 boxes(blank spaces for digits) and 5 different fruits(digits) are to be put in these boxes, where a box can hold a maximum of only 1 fruit. The number of such permutations are: ⁵P₃

By formula (a! is factorial a):

ᵃPₙ = \frac{a!}{(a-n)!}

⁵P₃ = \frac{5!}{(5-3)!}

⁵P₃ = \frac{5!}{2!}

⁵P₃ = \frac{5*4*3*2*1}{2*1}

⁵P₃= 60

This is the total count of possible numbers that can be formed.

Now, for a number to be greater than 800 and even; first digit should necessarily be 8. Last digit can be 4 or 6. Using these conditions, there are 6 possibilities. 854, 864, 874, 846, 856, 876 are the numbers.

The probability that number is even and greater than 800 is:

P=\frac{ favorable outcomes}{equally likely possible outcomes}

P=\frac{6}{60}

P=\frac{1}{10}

3 0
3 years ago
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