3 years ago

Given: P is a point on the perpendicular bisector, I of MN. Prove: PM = PN

Mathematics

1 answer:

Hatshy [7]3 years ago

5 0

Answer:

Step-by-step explanation:

I can't make specific statements about the proof because the midpoint is missing.

Givens

There are two right angles created by where the perpendicular bisector meats MN. Both are 90 degrees.

MN is bisected by the point on MN where the perpendicular meets MN

The Perpendicular Bisector is is common to both triangles.

Therefore the two triangles are congruent by SAS

PM = PN Parts contained in Congruent triangles are congruent.

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