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Dmitriy789 [7]
3 years ago
15

How to find the base of an isosceles when given one side​

Mathematics
1 answer:
MA_775_DIABLO [31]3 years ago
3 0
Double the side and subtract by 360
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Plz help i will mark brainliest
Alexus [3.1K]
2,3,and4 is 72
1 and 5 is 36
5 0
2 years ago
PLEASE HELP ME, ITS DUE RN
madam [21]

Answer:

here you go

Step-by-step explanation:

35+a+b+c=270

35+a=90

a+b=180

35+90+c=180

4 0
2 years ago
Find the distance<br> (8,1)(-2,-5)
Natalija [7]

Answer:

Square root of {(-2-8)^2+ (-5-1)^2}

Square root of {(-10)^2 + (-6)^2}

Square root of 100 +36

Square root of 136 = 11.66

Distance is 11.66

3 0
3 years ago
PLZ HELP ASAPP!!!!
juin [17]

Answer:

It is

Step-by-step explanation:

52² = 20² + 48²

2704 = 400 + 2304

2704 = 2704

Satisfies pythagoras theorem so right angle triangle

4 0
3 years ago
What is the equation of the asymptote? f (x) = 3^x-5+1<br> y=?
Natasha_Volkova [10]

The equation of the asymptote is y=1

Explanation:

The given equation is f(x)=3^{x-5}+1

We need to determine the horizontal asymptote of the equation.

The given equation is of the exponential function of the form f(x)=c \cdot n^{a x+b}+k and has a horizontal asymptote y=k

Hence, from the above equation, the value of k is 1.

Therefore, we have,

k=1

Thus, the horizontal asymptote is y=1

Therefore, the asymptote of the equation is y=1

4 0
3 years ago
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