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3 years ago

6

What are four division equations with 6 as the quotient

2 answers:

lisov135 [29]3 years ago

7 0

6 divided by 1=6
12 divided by 2=6
54 divided by 9=6
42 divided by 7=6

icang [17]3 years ago

5 0

6 <span>÷ 1 = 6
12 <span>÷ 2 = 6
54 <span>÷ 9 = 6
42 <span>÷ 7 = 6
Hope this helps! <span>☺
<span>▲</span></span></span></span></span></span>

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If the volume of a cylinder is 90 inches and what is the volume of a cone?

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The ans is D)1/3 in my point of view...

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Find the value of x to the nearest tenth

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3 years ago

Read 2 more answers

What is the area of the trapezoid if a = 10 b= 18 and h = 6 inches?

yanalaym [24]

[ Answer ]

$\boxed{\bold{84 \ In.^{2} }}$

[ Explanation ]

Formula For Area Of Trapezoid: $\boxed{\bold{\frac{a \ + \ b}{2}Height }}$

-----------------------------------------

A = 10

B = 18

H = 6

Plug Numbers Into Equation: $\boxed{\bold{\frac{10 \ + \ 18}{2}Height }}$

Solve

10 + 18 = 28

28 ÷ 2 = 14

14 · 6 = 84

Final Answer

84

$\boxed{\bold{[] \ Eclipsed \ []}}$

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3 years ago

Which set of ordered pairs does not represent a function?

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Step-by-step explanation:

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2 years ago

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Anastasy [175]

Answer:

$a_8=-128x^8-384x^7$

Step-by-step explanation:

The terms of the sequence are:

$x+3,-2x^2-6x,4x^3+12x^2,...$

We can rewrite the terms in factored form to get;

$x+3,-2x(x+3),4x^2(x+3),...$

We can see that the subsequent terms are obtained by multiplying the previous term by $-2x$ . This is called the common ratio.

Therefore the first term of this geometric sequence is $a_1=x+3$ and the common ratio is $r=-2x$ .

The nth term of a geometric sequence is given by: $a_n=a_1(r^{n-1})$ .

Let us substitute the first term, the common ratio, and $n=8$ to obtain:

$a_8=(x+3)(-2x)^{8-1}$

$a_8=(x+3)(-2x)^{7}$

$a_8=-128x^7(x+3)$

$a_8=-128x^8-384x^7$

3 0

3 years ago