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WITCHER [35]
1 year ago
8

The plans were made too hastily, without enough

Mathematics
1 answer:
Talja [164]1 year ago
7 0

The answer is (C). By referring to the plural word "plans" with a plural pronoun ("them"), it avoids the error of the original.

The reason was given for Wrong Answer A: Choice (A) contains an agreement mistake. It is incorrect to use the singular pronoun "it" to refer to the plural noun "plans."

The reason given for Wrong Answer B: In option (B), the alteration is done incorrectly. Hasty should be changed to "hastily" to modify the verb "manufactured."

Justification for Wrong Answer D: Improper alteration is involved in Option (D). Hasty should be changed to "hastily" to modify the verb "manufactured."

Justification for Wrong Answer E: Choice (E) has an agreement mistake. It is incorrect to use the singular pronoun "it" to refer to the plural noun "plans."

To learn more about it jumbled words, visit:

brainly.com/question/

#SPJ4

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What is the value of y when -5 =<br> = y - 7?<br> 9<br> a. -7<br> b.-11<br> C. -38<br> d. -52
weqwewe [10]

Answer:

2

Step-by-step explanation:

You have to cancel the -7 so you would add +7 to each side.

-7+7=0, -5+7= 2

y=2

Although this isn't an answer choice. Did you mistype something?

8 0
3 years ago
Find the equation of a line that is perpendicular to y = 3x – 5 and passes through the point (1, -3).
Svetradugi [14.3K]

keeping in mind that perpendicular lines have negative reciprocal slopes, let's check for the slope of the equation above

\begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}\qquad \qquad y = \stackrel{\stackrel{m}{\downarrow }}{3}x-5

well then therefore

\stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{3\implies \cfrac{3}{1}} ~\hfill \stackrel{reciprocal}{\cfrac{1}{3}} ~\hfill \stackrel{negative~reciprocal}{-\cfrac{1}{3}}}

so we're really looking for the equation of a line with slope of -1/3 and that passes through (1, -3 )

(\stackrel{x_1}{1}~,~\stackrel{y_1}{-3})\qquad \qquad \stackrel{slope}{m}\implies -\cfrac{1}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-3)}=\stackrel{m}{-\cfrac{1}{3}}(x-\stackrel{x_1}{1})\implies y+3=-\cfrac{1}{3}x+\cfrac{1}{3} \\\\\\ y=-\cfrac{1}{3}x+\cfrac{1}{3}-3\implies y=-\cfrac{1}{3}x-\cfrac{8}{3}

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2 years ago
How do you simplify numbers with exponents
tensa zangetsu [6.8K]
You write it out then you’ll get the exponent
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3 years ago
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djyliett [7]

Answer:

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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3 years ago
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