\left[x _{4}\right] = \left[ \frac{ - \left( -1\right) ^{\frac{3}{4}}\,\sqrt[4]{\left( 20 - 21\,z^{2}\right) }}{\sqrt[4]{4}}\right][x4]=[4√4−(−1)434√(20−21z2)]
I hope helping with u
If you are asking which is bigger then it is 4/6
Five hundred and sixty two divided by seven would be,
=80.28
42 divided by 7 =6 then u times 5 and 6 together . Then times 2 by 6 together so the answer is 30:12
Answer:
mean of this demand distribution = 100
Step-by-step explanation:
To find the mean of this demand distribution;
Mean = Expected vale = E[x]
for discrete provability function,
we say E[x] = ∑(x.p(x))
x p(x) x.p(x)
10 0.1 1
30 0.4 12
60 0.4 24
90 0.7 63
∴ ∑(x.p(x)) = ( 1 + 12 + 24 + 63 )
∑(x.p(x)) = 100
