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MakcuM [25]
3 years ago
6

BRAINLIESTTT. ASAP! PLEASE HELP ME :)

Mathematics
1 answer:
Vsevolod [243]3 years ago
5 0

Answer: Choice A

\frac{\sqrt{6}+\sqrt{2}}{4}

========================================================

Work Shown:

\cos(30) = \frac{\sqrt{3}}{2}

\cos(\frac{x}{2}) = \sqrt{\frac{1+\cos(x)}{2}

\cos(\frac{30}{2}) = \sqrt{\frac{1+\cos(30)}{2}

\cos(15) = \sqrt{\frac{1+\frac{\sqrt{3}}{2}}{2}

\cos(15) = \sqrt{\frac{\frac{2}{2}+\frac{\sqrt{3}}{2}}{2}

\cos(15) = \sqrt{\frac{\frac{2+\sqrt{3}}{2}}{2}

\cos(15) = \sqrt{\frac{2+\sqrt{3}}{4}}

\cos(15) = \frac{\sqrt{2+\sqrt{3}}}{\sqrt{4}}

\cos(15) = \frac{\sqrt{2+\sqrt{3}}}{2}

\cos(15) = \frac{0.5\sqrt{6}+0.5\sqrt{2}}{2}  

\cos(15) = \frac{\sqrt{6}+\sqrt{2}}{4}

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3 years ago
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<h2>3</h2>

Step-by-step explanation:

The equation of line passing through the two points is \frac{y-y_{1} }{x-x_{1} }=\frac{y_{2} -y_{1}}{x_{2} -x_{1}}

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The distance between two points is \sqrt{(y_{1}-y_{2} )^{2}+(x_{1}- x_{2} )^{2}}

Distance between origin and (2,6) is \sqrt{40}.

Distance between origin and (6,18) is \sqrt{360}

Scale factor is  \frac{distance\text{ }of\text{ }p_{2}\text{ from origin}}{distance \text{ } of \text{ } p_{1}\text{ from origin}}

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3 years ago
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Answer:

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