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MakcuM [25]
3 years ago
6

BRAINLIESTTT. ASAP! PLEASE HELP ME :)

Mathematics
1 answer:
Vsevolod [243]3 years ago
5 0

Answer: Choice A

\frac{\sqrt{6}+\sqrt{2}}{4}

========================================================

Work Shown:

\cos(30) = \frac{\sqrt{3}}{2}

\cos(\frac{x}{2}) = \sqrt{\frac{1+\cos(x)}{2}

\cos(\frac{30}{2}) = \sqrt{\frac{1+\cos(30)}{2}

\cos(15) = \sqrt{\frac{1+\frac{\sqrt{3}}{2}}{2}

\cos(15) = \sqrt{\frac{\frac{2}{2}+\frac{\sqrt{3}}{2}}{2}

\cos(15) = \sqrt{\frac{\frac{2+\sqrt{3}}{2}}{2}

\cos(15) = \sqrt{\frac{2+\sqrt{3}}{4}}

\cos(15) = \frac{\sqrt{2+\sqrt{3}}}{\sqrt{4}}

\cos(15) = \frac{\sqrt{2+\sqrt{3}}}{2}

\cos(15) = \frac{0.5\sqrt{6}+0.5\sqrt{2}}{2}  

\cos(15) = \frac{\sqrt{6}+\sqrt{2}}{4}

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4x + 8 = 7.2 + 5x

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before the recent house bonding there were 3212 houses in Fulton country now there are 3979 houses. How many houses did develope
lorasvet [3.4K]

Answer:

767 houses

Step-by-step explanation:

Initially there are 3212 houses in the city.

After the boom there are 3979 houses in the city.(due to boom there is an increase in the number of houses).

The number of houses developed by the developers is the difference between the number of houses before and after the boom.

The number of houses developed=3979-3212=767 houses

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3 years ago
At Munder Difflin Paper Company, the manager Mitchell Short randomly places golden sheets of paper inside of 30% of their paper
Korvikt [17]

Answer:

90.67% probability that John finds less than 7 golden sheets of paper

Step-by-step explanation:

For each container, there are only two possible outcomes. Either it contains a golden sheet of paper, or it does not. The probability of a container containing a golden sheet of paper is independent of other containers. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

At Munder Difflin Paper Company, the manager Mitchell Short randomly places golden sheets of paper inside of 30% of their paper containers.

This means that p = 0.3

14 of these containers of paper.

This means that n = 14

What is the probability that John finds less than 7 golden sheets of paper?

P(X < 7) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{14,0}.(0.3)^{0}.(0.7)^{14} = 0.0068

P(X = 1) = C_{14,1}.(0.3)^{1}.(0.7)^{13} = 0.0407

P(X = 2) = C_{14,2}.(0.3)^{2}.(0.7)^{12} = 0.1134

P(X = 3) = C_{14,3}.(0.3)^{3}.(0.7)^{11} = 0.1943

P(X = 4) = C_{14,4}.(0.3)^{4}.(0.7)^{10} = 0.2290

P(X = 5) = C_{14,5}.(0.3)^{5}.(0.7)^{9} = 0.1963

P(X = 6) = C_{14,6}.(0.3)^{6}.(0.7)^{8} = 0.1262

P(X < 7) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) = 0.0068 + 0.0407 + 0.1134 + 0.1943 + 0.2290 + 0.1963 + 0.1262 = 0.9067

90.67% probability that John finds less than 7 golden sheets of paper

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IRINA_888 [86]

Answer:

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Step-by-step explanation:

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