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Vinvika [58]
3 years ago
5

Identify the type of hypothesis test below. H0:X=10.2, Ha:X>10.2 Select the correct answer below: The hypothesis test is two-

tailed. The hypothesis test is left-tailed. The hypothesis test is right-tailed.
Mathematics
1 answer:
Ganezh [65]3 years ago
4 0

Answer:

The hypothesis test is right-tailed

Step-by-step explanation:

To identify a one tailed test, the claim in the case study tests for the either of the two options of greater or less than the mean value in the null hypothesis.

While for a two tailed test, the claim always test for both options: greater and less than the mean value.

Thus given this: H0:X=10.2, Ha:X>10.2, there is only the option of > in the alternative claim thus it is a one tailed hypothesis test and right tailed.

A test with the greater than option is right tailed while that with the less than option is left tailed.

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A charity sold 475 tickets to a dinner auction. If the charity raised $16,625 in ticket sales, what was the cost of one ticket?
Tanya [424]

Answer:

$35

Step-by-step explanation:

you have to divide the total money raised by the amount sold

16,625/475=35

each ticket was $35

and to make sure its correct you can always multiply the amount of 1 ticket to the amount sold

475*35=16,625

3 0
3 years ago
Whoaa buddy ole pal dont answer this it isnt a question
shutvik [7]

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Step-by-step explanation:

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3 years ago
Does anyone know how to solve this? It’s really starting to stress me out.
bekas [8.4K]

Answer:

π − 12

Step-by-step explanation:

lim(x→2) (sin(πx) + 8 − x³) / (x − 2)

If we substitute x = u + 2:

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lim(u→0) (sin(πu + 2π) + 8 − (u + 2)³) / u

Distribute the cube:

lim(u→0) (sin(πu + 2π) + 8 − (u³ + 6u² + 12u + 8)) / u

lim(u→0) (sin(πu + 2π) + 8 − u³ − 6u² − 12u − 8) / u

lim(u→0) (sin(πu + 2π) − u³ − 6u² − 12u) / u

Using angle sum formula:

lim(u→0) (sin(πu) cos(2π) + sin(2π) cos(πu) − u³ − 6u² − 12u) / u

lim(u→0) (sin(πu) − u³ − 6u² − 12u) / u

Divide:

lim(u→0) [ (sin(πu) / u) − u² − 6u − 12 ]

lim(u→0) (sin(πu) / u) + lim(u→0) (-u² − 6u − 12)

lim(u→0) (sin(πu) / u) − 12

Multiply and divide by π.

lim(u→0) (π sin(πu) / (πu)) − 12

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Use special identity, lim(x→0) ((sin x) / x ) = 1.

π (1) − 12

π − 12

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