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lubasha [3.4K]
3 years ago
6

Consider (11x + 9) − (?) = 6x + 8. Which expression is missing?

Mathematics
2 answers:
Alisiya [41]3 years ago
8 0
5x +1 is the answer to this equation.
o-na [289]3 years ago
5 0
The expression is (5x+1)
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9 cookies

5 plus 4 is 9
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Given f(x) = x3 – 2x2 – x + 2, <br><br> the roots of f(x)
anyanavicka [17]

f(x) = x³ – 2x² – x + 2

 

 0 = x3 – 2x2 – x + 2

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Help!! Lots of points
murzikaleks [220]

\frac{ {5}^{2} }{ {2}^{2} }  =  {( \frac{5}{2}) }^{2}
Since they are both squared.

Evaluating 5^2 and 2^2 and finding the quotient also works.

\frac{ {5}^{2} }{ {2}^{2} } =  \frac{5 \times 5}{2 \times 2}   =  \frac{25}{4}  = 6.25\\  \frac{ {5}^{2} }{ {2}^{2} }  =  {( \frac{5}{2} )}^{2}  = 2.5 \times 2.5 = 6.25
The third option, "Evaluate 5^2 and 2^2 ...," and the last option, "Rewrite the expression as (5/2)^2 ...," are the correct choices.
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5-2(a+3b)/2 When a=4 and b=1.
nirvana33 [79]

Hello macelynn190!

\huge \boxed{\mathfrak{Question} \downarrow}

\huge \tt \frac{5 - 2(a + 3b)}{2}

\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}

To solve this question we need to substitute the given values of 'a' & 'b' in the equation & then simplify it.

Given,

  • a = 4
  • b = 1

Now, substitute this in the place of 'a' & 'b'..

\large \tt \frac{5 - 2(a + 3b)}{2}  \\  =  \large   \underline{\underline{\tt \:  \frac{5 - 2((4) + 3(1))}{2} }}

Lastly, simplify it...

\large   \tt \:  \frac{5 - 2((4) + 3(1))}{2}  \\  =   \large \tt\frac{5 - 2(4 + 3)}{2}  \\  =  \large \tt \:  \frac{5 - 2(7)}{2}  \\  =  \large \tt \: \frac{5 - 14}{2}  \\  =  \large \tt\frac{-9}{2}  \\  = \large  \boxed{\boxed{  \bf \: -\frac{9}{2}=-4.5}}

  • The answer is <u>-</u><u>9</u><u>/</u><u>2</u><u> </u><u>or </u><u>-</u><u>4</u><u>.</u><u>5</u>

__________________

Hope it'll help you!

ℓu¢αzz ッ

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How do you multiply two fractions with different denominators?
IgorLugansk [536]
If you are multiplying fractions it doesn't matter if there are different denominators because you multiply straight across.
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