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blsea [12.9K]
3 years ago
13

A cone-shaped pile of sawdust has a base diameter of 38 feet, and is 14 feet tall. Find the volume of the pile

Mathematics
1 answer:
Romashka-Z-Leto [24]3 years ago
4 0

Answer:

Given: Diameter of cone = 38 feet and height of cone = 14 feet.

Volume of cone V with radius r is one-third the area of the base B times the height h.

i,e  V = \frac{1}{3} B \cdot h = \frac{1}{3} \pi r^2h  ......[1]

,where B = \pi r^2

First find the radius(r);

Using Diameter(D) = 2r

38 =2r

Divide both side by 2 we get;

\frac{38}{2} =\frac{2r}{2}

Simplify:

19 = r

or r =19 feet

Now, substitute the value of r = 19 feet and h = 14 feet in [1]    [ Use value of  \pi = \frac{22}{7} ]

then, we have:

V = \frac{1}{3} \pi r^2h = \frac{1}{3} \cdot  \frac{22}{7} \cdot (19)^2 \cdot (14)

or

V = =\frac{1}{3}\cdot 22 \cdot 19 \cdot 19 \cdot  2 = \frac{22 \cdot 19 \cdot 19 \cdot 2}{3}

or

V = \frac{15884}{3} =5,294.66667 ≈ 5,294.67 cubic feet.

therefore, the volume of pile is; ≈ 5,294.67 cubic feet.


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