Answer:
0.115
Step-by-step explanation:
Explanation:
Let M be the midpoint of AB. Then CM is the perpendicular bisector of AB. As such, center O is on CM, and OC is a radius (and CM). The tangent is perpendicular to that radius (and CM), so is parallel to AB, which is also perpendicular to CM.
If you need to go any further, you can show that triangles CMA and CMB are congruent, so (linear) angles CMA and CMB are congruent, hence both 90°.
Answer:
13 , 35
Step-by-step explanation:
Let's call one of the number x and the other y
x + y = 47
x - y = 21 and x = 21 + y if we use this expression in the first equation instead of x we can find the value of y
x + y = 47 ➡ y + y + 21 = 47 add like terms
2y +21 = 47
2y = 47 - 21
2y = 26
y = 13 the value of first number is 13
x + y = 47 we know y is 13 so we can replace it
x + 13 = 47
x = 35
Answer:
The sum of the two integers is 23
Step-by-step explanation:
Let one integer be x and the other integer be y
Then according to the statement "One positive integer is 3 greater than 4 times another positive integer.."
x be the integer that is One positive integer is 3 greater than 4 times another positive integer.
Then
x= 3+4y----------------------------------(1)
Product of the two integer is 76, this can written as
substituting the values of x from eq(1)
Solving the quadratic equation equation we get
here
a = 4
b= 3
c = -76
susbtituting the above values in the formula
y= 4 y = −4.75
Since in the question it is given that it is a positive integer
so y = 4
substituting y=4 in eq (1) we get,
x= 3+4(4)
x= 3+16
x= 19
The sum of the two integers
=> x + y
=> 19+4
=>23
Answer:
50% change in volume
Step-by-step explanation:
<h2>
This problem bothers on the mensuration of solid shapes.</h2>
In this problem we are to find the volume of the first cylinder and compare with the second cylinder.
Given data
Volume v = ?
Diameter d=
?
Radius r =
Height h=
we know that the volume of a cylinder is expressed as
Substituting our given data we have
The first cylinder as a volume of
The change in volume is
percentage =
%