Answer:
Answer: 84 meters squared. (i.e. 84m^2).
Step-by-step explanation:
Area of the path = total area of path and plot - plot area only
First, let’s find the area of the plot:
20m x 20m = 400m^2
The path is 1m wide and runs all the way around, so, it describes an ‘outer square’ of 22m x 22m (2 x 1m larger because there are 1m of the path on each side).
The area of this ‘outer square’ is equivalent to the ‘total area of path and plot’
22m x 22m = 484m^2
So:
Area of the path = total area of path and plot - plot area only
= 484 - 400 = 84m^2
Answer:
The space that the package would occupy is 45
cubic feet.
Step-by-step explanation:
The space that the package occupies is the volume of the cylinder. The volume of an object is the 3 dimensional capacity of the object.
Volume of a cylinder = 
h
where: r is the radius and h is the height of the cylinder.
Given that; h = 5 feet and r = 3 feet.
The required volume =
×
× 5
=
× 9 × 5
= 45
cubic feet
The space that the package would occupy is 45
cubic feet.
So this question is already perfectly set up. Since the 6 and -6 cancel you’ll be left with 5x + 3x which is 8x and -32 + 48 which is 16. 8x=16. Isolate x to get that x=2. Plug 2 back into one of the equations. 5(2) -6y = -32. Solve for y now. -10-32 equals -42. Divide -42 by -6 to get 7. So the final coordinate where the two equations will intersect is (2,7)