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pav-90 [236]
3 years ago
10

I need help with 25 and 26 plzz

Mathematics
1 answer:
Paha777 [63]3 years ago
8 0

Answer:

Step-by-step explanation:

25.

Combine like terms.

4t+7=-33

subtract 7 from both sides

4t=-40

divide both sides by 4

t=-10

26.

Subtract 2a from both sides

5=7a-16

add 16 to both sides

21=7a

divideby 7 on both sides

a = 3

I'd suggest getting the app photomath or using cymath to help you with these problems. they give you the answer and how to get it step by step

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Solve the system of equations using the elimination method. 1.Solve {x + 3y = -15
shutvik [7]

An equation is formed of two equal expressions. The solution is (-9,-2).

<h3>What is an equation?</h3>

An equation is formed when two equal expressions are equated together with the help of an equal sign '='.

Given the equation x + 3y = -15 and -3x + 2y = 23,

Step 1- Multiply the equations to make the coefficients match in either the x- or y-variable.

x + 3y = -15

3x + 9y = -45

Step2- After you multiply, add or subtract the two equations.

3x + 9y -3x + 2y = -45 + 23

Step 3- Then solve for the variables that is left.

11y = -22

y = -2

Step4- Substitute the value of y in any one of equations to solve for x.

x + 3(-2) = -15

x - 6 = -15

x = -9

Hence, The solution is (-9,-2).

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2 years ago
42.54 degrees is the same as 42 degrees______ '42"
pav-90 [236]
The answer is 24" hope this helps.
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3 years ago
Sviatoslav solved the quadratic equation x^2-x-1=0 by completing the square. In the process, he came up with the equivalent equa
zimovet [89]

Answer:

x=\frac{1+\sqrt5}{2} and  x=\frac{1-\sqrt5}{2}

and b=\frac{5}{4}

Step-by-step explanation:

We are given that a quadratic equation

x^2-x-1=0

We have to solve the equation by completing square and find the value of b.

(x)^2-2\times x\times \frac{1}{2}+(\frac{1}{2})^2-(\frac{1}{2})^2-1=0

(x-\frac{1}{2})^2-\frac{1}{4}-1=0

(x-\frac{1}{2})^2-\frac{1-4}{4}=0

(x-\frac{1}{2})-\frac{5}{4}=0

(x-\frac{1}{2})^2-(\frac{\sqrt5}{2})^2=0

(x-\frac{1}{2})^2=(\frac{\sqrt5}{2})^2

x-\frac{1}{2}=\frac{\sqrt5}{2} and x-\frac{1}{2}=-\frac{\sqrt5}{2}

x=\frac{\sqrt5}{2}+\frac{1}{2}=\frac{1+\sqrt5}{2}

And x=\frac{1}{2}-\frac{\sqrt5}{2}=\frac{1-\sqrt5}{2}

Therefore,x=\frac{1+\sqrt5}{2} and  x=\frac{1-\sqrt5}{2}

and b=\frac{5}{4}

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