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3 years ago

10

During a weekend sale, a store sold 85 DVDs for $19 each. What is the total amount of money, rounded to the nearest hundred, the

store made by selling DVDs?

1 answer:

Gekata [30.6K]3 years ago

8 0

Answer:

$1615.00

Step-by-step explanation:

You might be interested in

Determine whether this statement is true or false. if two lines have the same slope, their equations describe the same line.

maksim [4K]

Answer:

False

Step-by-step explanation:

When you say "slope", Im guessing your referring to the gradient (the steepness of the line).

If two lines have the same gradient their equations won't usually describe the same line because their 'y intercepts' will be different (the point in which the line crosses the y axis)

8 0

3 years ago

3 tims what will =28

goldenfox [79]

9.3 repeating is the answer.

4 0

3 years ago

Read 2 more answers

*Asymptotes*<br> g(x) =2x+1/x-3 <br><br> Give the domain and x and y intercepts

Nataly [62]

Answer: Assuming the function is $g(x)=\frac{2x+1}{x-3}$ :

The x-intercept is $(\frac{-1}{2},0)$ .

The y-intercept is $(0,\frac{-1}{3})$ .

The horizontal asymptote is $y=2$ .

The vertical asymptote is $x=3$ .

Step-by-step explanation:

I'm going to assume the function is: $g(x)=\frac{2x+1}{x-3}$ and not $g(x)=2x+\frac{1}{x}-3$ .

So we are looking at $g(x)=\frac{2x+1}{x-3}$ .

The x-intercept is when y is 0 (when g(x) is 0).

Replace g(x) with 0.

$0=\frac{2x+1}{x-3}$

A fraction is only 0 when it's numerator is 0. You are really just solving:

$0=2x+1$

Subtract 1 on both sides:

$-1=2x$

Divide both sides by 2:

$\frac{-1}{2}=x$

The x-intercept is $(\frac{-1}{2},0)$ .

The y-intercept is when x is 0.

Replace x with 0.

$g(0)=\frac{2(0)+1}{0-3}$

$y=\frac{2(0)+1}{0-3}$

$y=\frac{0+1}{-3}$

$y=\frac{1}{-3}$

$y=-\frac{1}{3}$ .

The y-intercept is $(0,\frac{-1}{3})$ .

The vertical asymptote is when the denominator is 0 without making the top 0 also.

So the deliminator is 0 when x-3=0.

Solve x-3=0.

Add 3 on both sides:

x=3

Plugging 3 into the top gives 2(3)+1=6+1=7.

So we have a vertical asymptote at x=3.

Now let's look at the horizontal asymptote.

I could tell you if the degrees match that the horizontal asymptote is just the leading coefficient of the top over the leading coefficient of the bottom which means are horizontal asymptote is $y=\frac{2}{1}$ . After simplifying you could just say the horizontal asymptote is $y=2$ .

Or!

I could do some division to make it more clear. The way I'm going to do this certain division is rewriting the top in terms of (x-3).

$y=\frac{2x+1}{x-3}=\frac{2(x-3)+7}{x-3}=\frac{2(x-3)}{x-3}+\frac{7}{x-3}$

$y=2+\frac{7}{x-3}$

So you can think it like this what value will y never be here.

7/(x-3) will never be 0 because 7 will never be 0.

So y will never be 2+0=2.

The horizontal asymptote is y=2.

(Disclaimer: There are some functions that will cross over their horizontal asymptote early on.)

6 0

3 years ago

3 3/4 -1 3/14 in simpilist form

lakkis [162]

For this case we must simplify the following expression:

$3 \frac {3} {4} -1 \frac {3} {14} =$

To do this, we convert the mixed numbers to improper fractions:

$\frac {4 * 3 + 3} {4} - \frac {14 * 1 + 3} {14} =\\\frac {15} {4} - \frac {17} {14} =\\\frac {14 * 15-4 * 17} {4 * 14} =\\\frac {210-68} {56} =\\\frac {142} {56} =\\\frac {71} {28} =\\2 \frac {15} {28}$

Answer:

$\frac {71} {28} = 2 \frac {15} {28}$

6 0

3 years ago

Complete the table for y=1/2x+3

andrew-mc [135]

X 0 2 4 -2 -4
y 3 4 5 2 1

6 0

3 years ago