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Finger [1]
3 years ago
11

A temperature-stable resistor is made by connecting a resistor made of silicon in series with one made of iron. If the required

total resistance is 1300 capital omega in a wide temperature range around 20degrees Celsius, what should be the resistances of the two resistors? The temperature coefficients of the resistivities for iron and silicon are: alphairon = 5.0times 10-3 K-1
Physics
1 answer:
sergij07 [2.7K]3 years ago
6 0

Answer:

R_{Si} = 81.25 ohm

R_{Fe} = 1218.75 ohm

Explanation:

As we know that the two resistors are made to combine so that we will get temperature stable resistor

so we will have

\alpha_i = 5.0 \times 10^{-3}

\alpha_s = -75 \times 10^{-3}

now we know that

R_1\alpha_1\Delta T + R_2\alpha_2\Delta T = 0

R_1 (5 \times 10^{-3}) - R_2(75 \times 10^{-3})= 0

R_1 = 15 R_2

also we know that

R_1 + R_2 = 1300

R_{Si} = 81.25 ohm

R_{Fe} = 1218.75 ohm

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(a) 50 rad/s

The angular speed of the CD is related to the linear speed by:

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When scanning the innermost part of the track, we have

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As in part a, the angular speed of the CD is given by

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When scanning the outermost part of the track, we have

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r = 58.0 mm = 0.058 m

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\omega=\frac{1.25 m/s}{0.058 m}=21.6 rad/s

(c) 5550 m

The maximum playing time of the CD is

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And we know that the linear speed of the track is

v = 1.25 m/s

If the track were stretched out in a straight line, then we would have a uniform motion, therefore the total length of the track would be:

d=vt=(1.25 m/s)(4,440 s)=5,550 m

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The angular acceleration of the CD is given by

\alpha = \frac{\omega_f - \omega_i}{t}

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Substituting into the equation, we find

\alpha=\frac{21.6 rad/s-50.0 rad/s}{4440 s}=-6.4\cdot 10^{-3} rad/s^2

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taurus [48]

Answer:

a. 150 J

b. 150 J

c. 0 J

d. 0 J

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The given parameters are;

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Where;

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Therefore, the work done by the weight = W × d_{wieght} = W × 0 m = 0 J

The work done by the weight = 0 J

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