Answer:
In any programming language, the assignment statement is written as shown.
a[0] = 2*a[4];
Explanation:
This scenario is explained in c++ language.
An array is declared as follows.
Datatype array_name[length];
The variable length denotes the number of elements in the array. It is also an integer variable.
An element in the array is written as arr[k], where value of k ranges from 0 to ( length-1 ).
The first element is written as array_name[0], second element is written as array_name[1], and so on.
The elements in the array are initialized as shown.
array_name[0] = value1;
array_name[1] = value2;
For the given scenario, an integer array a is declared.
The variable length will be initialized to 5, which means the array a has exactly 5 elements.
int length = 5;
int a[length];
The elements of array a are initialized as shown.
a[0] = 1;
a[1] = 2;
a[2] = 3;
a[3] = 4;
a[4] = 5;
As per the given scenario, the first element of the array, a[0], needs to be assigned a new value. This new value is twice the value of the last element of the array, a[4].
The assignment statement is written as shown.
a[0] = ( 2 * a[4]) ;
The above statement assigns twice the value of the last element to the first element.
Thus, after the above statement is executed, the old value of a[0] which is 1 is over written.
Now, a[0] will hold new value which is
( 2 * a[4] )
= ( 2 * 5 )
= 10.
The value of the first element, a[0], is changed from 1 to 10.
The above can be programmed as shown.
#include <iostream>
using namespace std;
int main() {
int length = 5;
int a[length];
a[0] = 1;
a[1] = 2;
a[2] = 3;
a[3] = 4;
a[4] = 5;
a[0] = (2*a[4]) ;
return 0;
}
