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sveticcg [70]
3 years ago
15

Assume that an array of integers named a that contains exactly five elements has been declared and initialized. Write a single s

tatement that assigns a new value to the first element of the array. This new value should be equal to twice the value stored in the last element of the array.
Computers and Technology
1 answer:
BlackZzzverrR [31]3 years ago
3 0

Answer:

In any programming language, the assignment statement is written as shown.

a[0] = 2*a[4];

Explanation:

This scenario is explained in c++ language.

An array is declared as follows.

Datatype array_name[length];

The variable length denotes the number of elements in the array. It is also an integer variable.

An element in the array is written as arr[k], where value of k ranges from 0 to ( length-1 ).

The first element is written as array_name[0], second element is written as array_name[1], and so on.

The elements in the array are initialized as shown.

array_name[0] = value1;

array_name[1] = value2;

For the given scenario, an integer array a is declared.

The variable length will be initialized to 5, which means the array a has exactly 5 elements.

int length = 5;

int a[length];

The elements of array a are initialized as shown.

a[0] = 1;

a[1] = 2;

a[2] = 3;

a[3] = 4;

a[4] = 5;

As per the given scenario, the first element of the array, a[0], needs to be assigned a new value. This new value is twice the value of the last element of the array, a[4].

The assignment statement is written as shown.

a[0] = ( 2 * a[4]) ;

The above statement assigns twice the value of the last element to the first element.

Thus, after the above statement is executed, the old value of a[0] which is 1 is over written.

Now, a[0] will hold new value which is

( 2 * a[4] )

= ( 2 * 5 )

= 10.

The value of the first element, a[0], is changed from 1 to 10.

The above can be programmed as shown.

#include <iostream>

using namespace std;

int main() {

   int length = 5;

   int a[length];    

   a[0] = 1;

   a[1] = 2;

   a[2] = 3;

   a[3] = 4;

   a[4] = 5;

   a[0] = (2*a[4]) ;

  return 0;      

}

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Answer:

Explanation:

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import re

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   wordList = re.split('\s', wordList)

   wordDict = {}

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       else:

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Explanation:

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Design pseudocode for a program that will permit a user to store exactly 50 numbers in an array. Create an array big enough to h
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Answer:

#include<stdio.h>

//declare a named constant

#define MAX 50

int main()

{

   //declare the array

   int a[MAX],i;

   //for loop to access the elements from user

   for(i=0;i<MAX;i++)

   {

      printf("\n Enter a number to a[%d]",i+1);

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  printf("\n The array elements are :");

  for(i=0;i<=MAX;i++)

  printf(" %d ",a[i]);

}

Explanation:

PSEUDOCODE INPUTARRAY(A[MAX])

REPEAT FOR I EQUALS TO 1 TO MAX

PRINT “Enter a number to A[I]”

READ A[I]

[END OF LOOP]

REPEAT FOR I EQUALS TO 1 TO MAX

PRINT A[I]

[END OF LOOP]

RETURN

ALGORITHM

ALGORITHM PRINTARRAY(A[MAX])

REPEAT FOR I<=1 TO MAX

PRINT “Enter a number”

INPUT A[I]

[END OF LOOP]

REPEAT FOR I<=1 TO MAX

PRINT A[I]

[END OF LOOP]

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