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Mrrafil [7]
3 years ago
15

Question 24 of 25 Use the quadratic formula to find the solutions to the equation. x² – 3x+1=0

Mathematics
1 answer:
user100 [1]3 years ago
3 0
I think the answer is B! Hope this helps!
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Which graph best represents the equation 2x + 4y equals negative 8
Hitman42 [59]
You have to solve for y
Subtract 2x to the other side
Divide both sides by 4
y=-1x/2-2
Graph D has a slope of -1/2 and a y-intercept of -2
6 0
3 years ago
Solve the equation for all values of x.<br> (8x+9)(49x^2-100)=0
Liono4ka [1.6K]

Answer:

x = \frac{-9}{8} , \frac{-10}{7} , \frac{10}{7}

Step-by-step explanation:

8x+9=0

8x=-9

x = \frac{-9}{8}

or

49x^{2}-100 = 0

(7x)^{2} -10^{2} =0,

(7x+10)(7x-10)=0

7x+10=0, 7x-10=0

7x=-10, 7x=10

x=-\frac{-10}{7}, x = \frac{10}{7}

4 0
2 years ago
Find the values of &lt; and y.<br> (8x + 7)<br> 5yº<br> (7y -- 34)<br> = (2x - 4)^
Lilit [14]

Answer:

x = 11

y = 17

Step-by-step explanation:

We know that opposite angles (or vertical angles) are equal.

So

8x + 7 = 9x - 4

Subtract 8x from both sides of the equation

8x - 8x + 7 = 9x - 8x - 4

7 = x - 4

Add 4 to both sides of the equation

7 + 4 = x - 4 + 4

11 = x

Looking at the other 2 angles,

5y = 7y - 34

Subtract 7 y from both sides of the equation

5y - 7y = 7y - 7y - 34

-2y = -34

Divide both sides by -2

-2y/-2 = -34/-2

y = 17

6 0
3 years ago
Read 2 more answers
What is the slope of a line perpendicular to the line whose equation is
GenaCL600 [577]

Answer:

The slope or incline is -5

Step-by-step explanation:

rewrite to get the form

y = ...

x - 5y = -10

- 5y = -10 -x

divide left and right if the = sign by -5 gives:

(-5/-5)y = (-1/-5)x + (-10/-5)

y = 1/5x +2

So the incline is 1/5

a perpendicular line has an incline of -1 *5/1 = -5

The slope or incline is -5

4 0
3 years ago
A line passes through (−1, 7) and (2, 10).
Pachacha [2.7K]
The slope m of a line through points A(x_1, y_1) and B(x_2, y_2)  is given by :<span>

\displaystyle{m = \frac{y_2-y_1}{x_2-x_1}&#10;



Thus, the slope of the line passing through points </span><span>(−1, 7) and (2, 10) is 

</span>\displaystyle{m= \frac{10-7}{2-(-1)}= \frac{3}{3}=1
<span>

The equation of a line with slope m passing through a point P(a, b) is given by
                                        (y-b)=m(x-a).


We can consider any of the points (-1, 7), or (2, 10). Let's choose (2, 10):

                                        y-10=1(x-2)
                                        y-10=x-2
                                           y-x=-2+10
                                           y-x=8
                                       

  Answer: </span><span>C. −x+y=8</span>
7 0
3 years ago
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