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Arte-miy333 [17]
3 years ago
12

1/1 1/4 1/9 what's the pattern​

Mathematics
2 answers:
ad-work [718]3 years ago
5 0

Answer:

adding a fifth

Step-by-step explanation:

monitta3 years ago
4 0

Answer:

adding a fifth

Step-by-step explanation:

duhhhhhhhhhhhh

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Halp me plez I dont wanna fail ( MUST BE A EXPRESSION)
Scilla [17]

Answer:

2x+15=33

Step-by-step explanation:

Let n be the number of days he has been doing sit ups, not counting the first day. Since he does 2 more sit-ups for each day, then the number of additional sit-ups is 2n.

Since he started doing  15 sit-ups on the first day, the total number of sit-ups

after x days would be 2n+15.

Since he did a total of 33 sit ups today, then 2n+15=33

4 0
3 years ago
Z wants to buy five shirts worth 34 dollars each and three baseball caps worth 31
ella [17]

Answer:

$199.50

Step-by-step explanation:

10% discount of $34 = 10/100*34 = $3.40

so, a single shirt costs $34-$3.40 = $30.60

half off = 50% discount of $31 = 50/100*31 = $15.50

so, a single cap costs $31-$15.50 = $15.50

so, 5 shirts and 3 caps cost now

5*$30.60 + 3*$15.50 = $153 + $46.50 = $199.50

but careful - can this be a trick question ?

the phrasing of the problem description can also suggest that the discounts are only listed to confuse us and are already included in the mentioned prices ("worth" $34 - what does that mean ? because including the discounts they are currently "worth" their prices).

then it would just plainly be

5*$34 + 3*$31 = $170 + $93 = $263

4 0
3 years ago
The class sizes of elementary school classes in a public school district are normally distributed with an unknown population mea
weqwewe [10]

Answer: (17.14,\ 22.86)

Step-by-step explanation:

The confidence interval estimate for the population mean is given by :-

\overline{x}\pm ME, where \overline{x} is the sample mean and ME  is the margin of error.

Given : Sample mean: \overline{x}=20

The margin of error for a 98% confidence interval estimate for the population mean using the Student's t-distribution : ME=2.86

Now, the confidence interval estimate for the population mean will be :-

20\pm2.86=(20-2.86,\ 20+2.86)=(17.14,\ 22.86)

Hence, the 98% confidence interval estimate for the population mean using the Student's t-distribution =  (17.14,\ 22.86)

8 0
3 years ago
Find the magnitude of 6+2i
Svetradugi [14.3K]
For complex number, the magnitude is pretty straight forward:

sqrt(6^2 + 2^2) = sqrt(40)

For any a + bi, the magnitude will be sqrt(a^2 + b^2)
4 0
3 years ago
To change the 0.32 into percentage, I need to
Westkost [7]
Move the dot twice to the right
7 0
2 years ago
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