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denis-greek [22]
3 years ago
6

What is the answer to w/2 +7=w/3+9?

Mathematics
2 answers:
Cerrena [4.2K]3 years ago
7 0
1. <span>Multiply both sides by </span>6<span> (the LCM of </span><span>2, 3,</span><span>)

3w + 42 = 2w + 54

</span>2. Subtract 42 from both sides

3w = 2w + 54 - 42

3. <span>Simplify 2w + 54 - 42 to 2w + 12

3w = 2w + 12

4. </span><span>Subtract 2w from both sides 

3w - 2w = 12

5. </span><span>Simplify 3w - 2w to w

w=12 

Your answer is 12</span>
Svetlanka [38]3 years ago
6 0
W/2 - w/3 = 9-7
3w - 2w = 9-7
W = 2
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GarryVolchara [31]

Answer:

\mu_p -\sigma_p = 0.74-0.0219=0.718

\mu_p +\sigma_p = 0.74+0.0219=0.762

68% of the rates are expected to be betwen 0.718 and 0.762

\mu_p -2*\sigma_p = 0.74-2*0.0219=0.696

\mu_p +2*\sigma_p = 0.74+2*0.0219=0.784

95% of the rates are expected to be betwen 0.696 and 0.784

\mu_p -3*\sigma_p = 0.74-3*0.0219=0.674

\mu_p +3*\sigma_p = 0.74+3*0.0219=0.806

99.7% of the rates are expected to be betwen 0.674 and 0.806

Step-by-step explanation:

Check for conditions

For this case in order to use the normal distribution for this case or the 68-95-99.7% rule we need to satisfy 3 conditions:

a) Independence : we assume that the random sample of 400 students each student is independent from the other.

b) 10% condition: We assume that the sample size on this case 400 is less than 10% of the real population size.

c) np= 400*0.74= 296>10

n(1-p) = 400*(1-0.74)=104>10

So then we have all the conditions satisfied.

Solution to the problem

For this case we know that the distribution for the population proportion is given by:

p \sim N(p, \sqrt{\frac{p(1-p)}{n}})

So then:

\mu_p = 0.74

\sigma_p =\sqrt{\frac{0.74(1-0.74)}{400}}=0.0219

The empirical rule, also referred to as the three-sigma rule or 68-95-99.7 rule, is a statistical rule which states that for a normal distribution, almost all data falls within three standard deviations (denoted by σ) of the mean (denoted by µ). Broken down, the empirical rule shows that 68% falls within the first standard deviation (µ ± σ), 95% within the first two standard deviations (µ ± 2σ), and 99.7% within the first three standard deviations (µ ± 3σ).

\mu_p -\sigma_p = 0.74-0.0219=0.718

\mu_p +\sigma_p = 0.74+0.0219=0.762

68% of the rates are expected to be betwen 0.718 and 0.762

\mu_p -2*\sigma_p = 0.74-2*0.0219=0.696

\mu_p +2*\sigma_p = 0.74+2*0.0219=0.784

95% of the rates are expected to be betwen 0.696 and 0.784

\mu_p -3*\sigma_p = 0.74-3*0.0219=0.674

\mu_p +3*\sigma_p = 0.74+3*0.0219=0.806

99.7% of the rates are expected to be betwen 0.674 and 0.806

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In this case, you would multiply 20000 by 1.9, since 1.9 is the decimal form of 190%.

Solve:

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Answer:

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Answer:

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Step-by-step explanation:

Given

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After the cut-out, the cylinder has a volume of:

V = \pi [R^2 -r^2]h

So, we have:

V = 3.14* [6^2 -5^2]*15

V = 3.14* [36 -25]*15

V = 3.14* 11*15

V = 518cm^3

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