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sashaice [31]
3 years ago
6

Hiromi is painting the front and back of a barn. Each can of paint covers 32 square feet. How many cans of paint does Hiromi nee

d to cover the entire front and back of the barn?
Mathematics
1 answer:
densk [106]3 years ago
4 0
I need more information about the dimensions of the barn
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5,5.08,5.8,8.05,8.5 :))))
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the table shows the cost of the daycare for Lucy's dog this week her dog went 3 full days of day care and 2 half days of day car
drek231 [11]

An expression for the total cost of the daycare for Lucy's dog this week is T = 3F + 2H and the total cost is equal to $114.

<h3>How to write an expression for the total cost?</h3>

In this exercise, you're required to write an expression for the total cost of the daycare for Lucy's dog this week. Thus, we would assign a variable to the cost for full-day and half-day day care as follows:

  • Let the cost for full-day be F.
  • Let the cost for half-day be H.
  • Let total cost be T.

Thus, the total cost of the daycare is given by:

T = 3F + 2H

Evaluating the expression, we have:

T = 3(28) + 2(15)

T = 84 + 30

T = $114.

Read more on expressions here: brainly.com/question/12189823

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2 years ago
True or False? A secant is a line or segment that passes through a point on the circle and the center of the circle.
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3 years ago
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A random sample of 100 people was taken. Eighty of the people in the sample favored Candidate A. We are interested in determinin
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Answer:

Option b - not significantly greater than 75%.

Step-by-step explanation:

A random sample of 100 people was taken i.e. n=100

Eighty of the people in the sample favored Candidate i.e. x=80

We have used single sample proportion test,

p=\frac{x}{n}

p=\frac{80}{100}

p=0.8

Now we define hypothesis,

Null hypothesis H_0 : candidate A is significantly greater than 75%.

Alternative hypothesis H_1 : candidate A is not significantly greater than 75%.

Level of significance \alpha=0.05

Applying test statistic Z -proportion,

Z=\frac{\widehat{p}-p_0}{\sqrt{\frac{p_0(1-p_0)}{n}}}

Where, \widehat{p}=80\%=0.80 and p=75%=0.75

Substitute the values,

Z=\frac{0.80-0.75}{\sqrt{\frac{0.75(1-0.75)}{100}}}

Z=\frac{0.80-0.75}{\sqrt{\frac{0.1875}{100}}}

Z=\frac{0.05}{0.0433}

Z=1.1547

The p-value is

P(Z>1.1547)=1-P(Z

P(Z>1.1547)=1-0.8789

P(Z>1.1547)=0.1241

Now, the p-value is greater than the 0.05.

So we fail to reject the null hypothesis and conclude that the A is not significantly greater than 75%.

Therefore, Option b is correct.

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3 years ago
A pyramid at a museum has a height of 21 meters and a square base with side lengths of 30 meters. 21 m 30 m What is the approxim
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Step-by-step explanation:

Put numbers into calculator

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