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Studentka2010 [4]
3 years ago
10

What is the sum of one-sixth of x and 2.8?

Mathematics
1 answer:
Murljashka [212]3 years ago
7 0
The answer is 2.8x! hope it helps
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Geometry page 1 help please !
victus00 [196]

Answer:

16) y=\frac{1}{4}x +5

17) y = -x - 4

18) y = -2x - 1

19) y = -2x

20)y=\frac{-5}{3} -3

Step-by-step explanation:

With the two points you find the slope using \frac{y_{2}-y_{1}  }{x_{2}-x_{1} }

Then using that slope, plug the slope in with one of the points values of x and y into the point slope formula, and smiplify that into the y-intercept formula.

6 0
3 years ago
An inequality is shown below. x + 2.5 < 20 What is the greatest value of x from the set {10.5, 12.5, 17.5, 19.5} that makes t
34kurt
C is the final answer :)
4 0
3 years ago
Jenny's frog made one jump of 2.34 m. Christina's frog made jumps of 1.22 m and 0.89 m. How much further did Jenny's frog jump i
Alinara [238K]
The answer is A, i hope that i helped
7 0
3 years ago
Solve for x, 0 ≤ x ≤2π (2cosx-1)(2sinx+√3 ) = 0
vladimir1956 [14]

Answer:

x = π/3, x = 5π/3, x = 4π/3

Step-by-step explanation:

Let's split the given equation (2cosx-1)(2sinx+√3 ) = 0 into two parts, and solve each separately. These parts would be 2cos(x) - 1 = 0, and 2sin(x) + √3  = 0.

2\cos \left(x\right)-1=0,\\2\cos \left(x\right)=1,\\\cos \left(x\right)=\frac{1}{2}

Remember that the general solutions for cos(x) = 1/2 are x = π/3 + 2πn and x = 5π/3 + 2πn. In this case we are given the interval 0 ≤ x ≤2π, and therefore x = π/3, and x = 5π/3.

Similarly:

\:2\sin \left(x\right)+\sqrt{3}=0,\\2\sin \left(x\right)=-\sqrt{3},\\\sin \left(x\right)=-\frac{\sqrt{3}}{2}

The general solutions for sin(x) = - √3/2 are x = 4π/3 + 2πn and x = 5π/3 + 2πn. Therefore x = 4π/3 and x = 5π/3 in this case.

So we have x = π/3, x = 5π/3, and x = 4π/3 as our solutions.

5 0
3 years ago
PLEASE HELP
harina [27]
Ok I’m im not sure you can ask someone else sorry
3 0
3 years ago
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