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padilas [110]
2 years ago
8

6 1/2 equals 1 1/4 + n

Mathematics
1 answer:
11111nata11111 [884]2 years ago
6 0

Answer:

yhy

Step-by-step explanation:

uhuj

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Calculate using Cauchys integral formula
zhuklara [117]

Answer:

9πi/2

Step-by-step explanation:

\oint\limits_C {\frac{5z^{2}+4}{(z-1)(z+3)} } \, dz,\ C: |z|=2

Let f(z) = (5z² + 4) / (z + 3).

\oint\limits_C {\frac{f(z)}{z-1} } \, dz,\ C: |z|=2

Using Cauchy's integral formula:

2\pi i\ f(1)\\2\pi i\ (\frac{5(1)^{2}+4}{1+3}) \\2\pi i\ (\frac{9}{4}) \\\frac{9\pi i}{2}

5 0
3 years ago
Find the area of a rhombus having perimeter 80 em and one diagonal 24 cm.<br>​
horsena [70]
A=384 cm^2 hope this helped!
4 0
3 years ago
I don't get thissssssssssssssssss
andrew11 [14]

Answer:

west wing ,north wing, east wing and south wing

Step-by-step explanation:

west wing = 5 4/11 =59/11 =5.3636...

north wing = 37/7 =5.25...

east wing = 5.21

south wing = 5.125

8 0
3 years ago
Use the elimination method to solve this system.
leva [86]

Answer:

The solution for this system is: x = -1, y = 1

Step-by-step explanation:

The problem states that we have to solve this system by the elimination method

In the elimination method, we transform the system in such a way that one variable can cancel each other. With this, we find the result of the other variable. Then, we can replace the variable we found in any of the equations, and we have the value of the variable that we had initially canceled.

In this problem, we have the following system:

1) -6x + 5y = 1

2) 6x + 4y = -10

If we add equations 1) and 2), the variable x is going to be eliminated

1) + 2)

-6x + 6x + 5y + 4y = 1 - 10

9y = -9

y = \frac{-9}{9}

y = -1

Now, we can replace the value of y in any of the equations, to find x:

I will replace in equation 2)

6x + 4y = -10

6x + 4(-1) = -10

6x = -6

x = \frac{-6}{6}

x = -1

The solution for this system is: x = -1, y = 1

5 0
3 years ago
URGENT HELP ME OUT PLEASE 20 points <br><br> What are the solutions to the quadratic equation?
icang [17]
I think it’s c hope this helps you :)
8 0
2 years ago
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